Write the number 0.000 000 7 in standard form.

TiliK225 [7]

That is the answer for the first one

6 0

2 years ago

Investments historically have doubled every 9 years. if you start with 2,000 investment, how much money would you have after 45

77julia77 [94]

Answer: 64,000

Equation: 2,000*2^(45/9)

4 0

3 years ago

How to I put x>-2.5 on a number line?

AysviL [449]

Answer:

Open circle. Points right

Step-by-step explanation:

The reason for it is because this symbol > represents greater than when it comes to inequalities. When it is an open circle that means that you are not including the number. So that also means that the -2.5 is not included to the inequality equation but it can be any other number other than that number.

4 0

2 years ago

a copy shot prints 5,493 pages they use the pages to make 68 same size booklets about how many pages are in each booklet

Aliun [14]

Answer:

80 pages

Step-by-step explanation:

Given:

Number of pages printed = 5493

Number of booklets made = 68

Let each booklet use 'x' pages.

So, pages used by 68 booklets is given by unitary method and is equal to:

$=68\times x\\=68x$

Now, total number of pages are 5493.

Therefore, the pages used by the 68 booklets should be less than or equal to the total number of pages available. So,

$68x=5493\\\textrm{Dividing both sides by 68,we get:}\\x=\frac{5493}{68}=80.8\approx 80(\textrm{As number of pages can't be in decimal})$

Therefore, the number of pages in each booklet is 80.

3 0

3 years ago

Best known for its testing program, ACT, Inc., also compiles data on a variety of issues in education. In 2004 the company repor

GarryVolchara [31]

Answer:

$\mu_p -\sigma_p = 0.74-0.0219=0.718$

$\mu_p +\sigma_p = 0.74+0.0219=0.762$

68% of the rates are expected to be betwen 0.718 and 0.762

$\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696$

$\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784$

95% of the rates are expected to be betwen 0.696 and 0.784

$\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674$

$\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806$

99.7% of the rates are expected to be betwen 0.674 and 0.806

Step-by-step explanation:

Check for conditions

For this case in order to use the normal distribution for this case or the 68-95-99.7% rule we need to satisfy 3 conditions:

a) Independence : we assume that the random sample of 400 students each student is independent from the other.

b) 10% condition: We assume that the sample size on this case 400 is less than 10% of the real population size.

c) np= 400*0.74= 296>10

n(1-p) = 400*(1-0.74)=104>10

So then we have all the conditions satisfied.

Solution to the problem

For this case we know that the distribution for the population proportion is given by:

$p \sim N(p, \sqrt{\frac{p(1-p)}{n}})$

So then:

$\mu_p = 0.74$

$\sigma_p =\sqrt{\frac{0.74(1-0.74)}{400}}=0.0219$

The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ).

$\mu_p -\sigma_p = 0.74-0.0219=0.718$

$\mu_p +\sigma_p = 0.74+0.0219=0.762$

68% of the rates are expected to be betwen 0.718 and 0.762

$\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696$

$\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784$

95% of the rates are expected to be betwen 0.696 and 0.784

$\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674$

$\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806$

99.7% of the rates are expected to be betwen 0.674 and 0.806

5 0

3 years ago