Let AB be a chord of the given circle with centre and radius 13 cm.
Then, OA = 13 cm and ab = 10 cm
From O, draw OL⊥ AB
We know that the perpendicular from the centre of a circle to a chord bisects the chord.
∴ AL = ½AB = (½ × 10)cm = 5 cm
From the right △OLA, we have
OA² = OL² + AL²
==> OL² = OA² – AL²
==> [(13)² – (5)²] cm² = 144cm²
==> OL = √144cm = 12 cm
Hence, the distance of the chord from the centre is 12 cm.
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Answer:
The y-intercept of function g located at (0,2)
Step-by-step explanation:
Function :
g(x) is a transformation of the quadratic parent function
We are supposed to find the where is the y-intercept of function g located
y intercept = the y-coordinate of a point where a line, curve, or surface intersects the y-axis i.e. x =0
So, substitute x = 0 in function
g(x)=x^2+2
g(0)=0^2+2
g(0)=2
So,(x,y)=(0,2)
So, The y-intercept of function g located at (0,2)