Answer:
80° , 100°, 80°
Step-by-step explanation:
∠ 1 and ∠ 2 form a straight line and sum to 180° , then
2x + 40 + 2y + 40 = 180
2x + 2y + 80 = 180 ( subtract 80 from both sides )
2x + 2y = 100 → (1)
∠ 1 and ∠ 3 are vertical angles and are congruent , then
2x + 40 = x + 2y ( subtract x from both sides )
x + 40 = 2y ( subtract 40 from both sides )
x = 2y - 40 → (2)
Substitute x = 2y - 40 into (1)
2(2y - 40) + 2y = 100
4y - 80 + 2y = 100
6y - 80 = 100 ( add 80 to both sides )
6y = 180 ( divide both sides by 6 )
y = 30
Substitute y = 30 into (2)
x = 2(30) - 40 = 60 - 40 = 20
Thus x = 20 and y = 30
Then
∠ 1 = 2x + 40 = 2(20) + 40 = 40 + 40 = 80°
∠ 2 = 2y + 40 = 2(30) + 40 = 60 + 40 = 100°
∠3 = x + 2y = 20 + 2(30) = 20 + 60 = 80°
The bisector of an angle is a segment or a ray that passes through the vertex and splits it into two congruent angles.
Hope this is of great help to you, and happy studying~!
~Mistermistyeyed.
Answer:
im only doing this bc im forced to
Answer:
No
Step-by-step explanation:
We have to find that a quadratic polynomial equation with real coefficient can have one real solution and one complex solution.
quadratic equation is given by

It can be written as the product of linear factors

Where
are solutions of the given polynomial equation.
No , a quadratic polynomial equation can not have one real solution and one complex solution because complex root are always in paired not a single.
A quadratic equation have two roots only.
If a quadratic equation have complex root then the equation have both complex root .
If a equation have real root then it have both real.
Therefore, a quadratic equation can not have one real and one compelx solution.
The Gauss-Jordan elimination method different from the Gaussian elimination method in that unlike the Gauss-Jordan approach, which reduces the matrix to a diagonal matrix, the Gauss elimination method reduces the matrix to an upper-triangular matrix.
<h3>
What is the Gauss-Jordan elimination method?</h3>
Gauss-Jordan Elimination is a technique that may be used to discover the inverse of any invertible matrix as well as to resolve systems of linear equations.
It is based on the following three basic row operations that one may apply to a matrix: Two of the rows should be switched around. Multiply a nonzero scalar by one of the rows.
Learn more about Gauss-Jordan elimination method:
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