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3 years ago

Help me PLEASEEEEEEEEEEEEE

Mathematics

1 answer:

maxonik [38]3 years ago

6 0

Answer:

D. 144

Step-by-step explanation:

Find volume of shipping container:

2 2/3 = 8/3

2 x 1 = 2

8/3 x 2/1 = 16/3

Find volume of cube:

1/3 x 1/3 = 1/9 x 1/3 = 1/27

Find how many boxes fit in container:

16/3 ÷ 1/27

16/3 x 27/1

Simplify:

16/1 x 9/1 = 144/1

Answer: 144

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Lia finds a second dress that was originally $72.00 and now was marked 15% off. How much did she pay for the second dress?

dybincka [34]

Answer:

The answer is $61.20

Step-by-step explanation:

First you multiply 72 by .15 (which is 15% converted to a decimal), which gives you 10.8. You then subtract 10.8 from 72.

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3 years ago

Negative 3 less then 4.9 times a number, x, is the same as 12.8

NNADVOKAT [17]

Answer: (4.9x) - 3

Step-by-step explanation: the reason i didn't add an extra line thing is because the negative becomes the minus. the 4.9 is self evident

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3 years ago

SOLVE. (5n)÷(30m)+(2m+4n)÷(30m)

Andru [333]

Note, since both factors have the same denominator, we can add the numerators together.

Numerator :

5n + (2m + 4n) = 5n + 2m + 4n = 9n + 2m

Denominator :

30m

Thus,

= (9n + 2m) / 30m

6 0

3 years ago

Read 2 more answers

Find the perimeter of a triangle with sides 15 inches, 15 inches, and 21 inches length.

Degger [83]

find the perimeter of a triangle with sides 15 inches, 15 inches, and 21 inches length

To find the perimeter of a triangle we add all the sides of the triangle

The length of the sides of the triangle are given as 15 inches, 15 inches, and 21 inches

Perimeter of a triangle =

15 inches + 15 inches + 21 inches = 51 inches

So 51 inches is the perimeter

3 0

3 years ago

Water is added to a cylindrical tank of radius 5 m and height of 10 m at a rate of 100 L/min. Find the rate of change of the wat

nirvana33 [79]

Answer:

$V = \pi r^2 h$

For this case we know that $r=5m$ represent the radius, $h = 10m$ the height and the rate given is:

$\frac{dV}{dt}= \frac{100 L}{min}$

$Q = 100 \frac{L}{min} *\frac{1m^3}{1000L}= 0.1 \frac{m^3}{min}$

And replacing we got:

$\frac{dh}{dt}=\frac{0.1 m^3/min}{\pi (5m)^2}= 0.0012732 \frac{m}{min}$

And that represent $0.127 \frac{cm}{min}$

Step-by-step explanation:

For a tank similar to a cylinder the volume is given by:

$V = \pi r^2 h$

For this case we know that $r=5m$ represent the radius, $h = 10m$ the height and the rate given is:

$\frac{dV}{dt}= \frac{100 L}{min}$

For this case we want to find the rate of change of the water level when h =6m so then we can derivate the formula for the volume and we got:

$\frac{dV}{dt}= \pi r^2 \frac{dh}{dt}$

And solving for $\frac{dh}{dt}$ we got:

$\frac{dh}{dt}= \frac{\frac{dV}{dt}}{\pi r^2}$

We need to convert the rate given into m^3/min and we got:

$Q = 100 \frac{L}{min} *\frac{1m^3}{1000L}= 0.1 \frac{m^3}{min}$

And replacing we got:

$\frac{dh}{dt}=\frac{0.1 m^3/min}{\pi (5m)^2}= 0.0012732 \frac{m}{min}$

And that represent $0.127 \frac{cm}{min}$

5 0

4 years ago