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3 years ago

P please please pa help

Mathematics

1 answer:

serious [3.7K]3 years ago

8 0

Move the discount sign two places to the left and divide the regular price by that decimal. Then take that price and put it in the selling price and take the selling price and subctract that from the original price

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Almost all medical schools in the United States require students to take the Medical College Admission Test (MCAT). To estimate

yKpoI14uk [10]

Answer:

a) 0.5588

b) 0.9984

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 24

Standard Deviation, σ = 6.4

We are given that the distribution of score is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(score between 20 and 30)

$P(20 \leq x \leq 30) = P(\displaystyle\frac{20 - 24}{6.4} \leq z \leq \displaystyle\frac{30-24}{6.4}) = P(-0.62 \leq z \leq 0.94)\\\\= P(z \leq 0.94) - P(z < -0.62)\\= 0.8264 - 0.2676 = 0.5588 = 55.88\%$

$P(20 \leq x \leq 30) = 55.88\%$

b) Sampling distribution

Sample size, n = 22

The sample will follow a normal distribution with mean 24 and standard deviation,

$s = \dfrac{\sigma}{\sqrt{n}} = \dfrac{6.4}{\sqrt{22}} =1.36$

c) P(mean score of sample is between 20 and 30)

$P(20 \leq x \leq 30) = P(\displaystyle\frac{20 - 24}{1.36} \leq z \leq \displaystyle\frac{30-24}{1.36}) = P(-2.94 \leq z \leq 4.41)\\\\= P(z \leq 4.41) - P(z < -2.94)\\= 1 - 0.0016 = 0.9984 = 99.84\%$

$P(20 \leq x \leq 30) =99.84\%$

5 0

4 years ago

How many grams of a 10% cream must be mixed with 2% cream to prepare 60 grams of a 5% cream?

Blizzard [7]

Answer:

22.5 grams of 10% cream is mixed with 37.5 grams of 2 % cream to prepare 60 grams of 5% cream.

Step-by-step explanation:

Let x grams of 10% cream is mixed with y grams of 2 % cream to prepare 60 grams of 5% cream.

So, x + y = 60 ............ (1) and

$x\times \frac{10}{100} + y \times \frac{2}{100} = 60 \times \frac{5}{100}$

⇒ 10x + 2y = 300

⇒ 5x + y = 150 ............ (2)

Now, solving equations (1) and (2) we get,

4x = 150 - 60 = 90

⇒ x = 22.5 grams

So, y = 60 - x = 37.5 grams. (Answer)

3 0

3 years ago

I need some help with this problem.

ziro4ka [17]

Answer:

Step-by-step explanation:

hope it helps :)

brainliest pls? have a good day/night

6 0

4 years ago

(-155)^4/19^2 : (155/19)^3

Snezhnost [94]

Answer:

$\frac{ { - 155}^{4} }{ {19}^{2} } \div { (\frac{155}{19} }) ^{3} = \\ \frac{ { - 155}^{4} }{{19}^{2} } \div \frac{ {155}^{3} }{ {19}^{3} } = \\ \frac{ { - 155}^{4} }{ {19}^{2} } \times \frac{ {19}^{3} }{ {155}^{3} } = \\ - 155 \times 19 = - 2945$

7 0

3 years ago

The expression 96^2 - 95^2 is a difference of two squares. How can you use the factors (96 - 95)(96 +95) to make it easier to si

crimeas [40]

The first factor simplifies to 1 and the second factor simplifies to 191, which are very easy to evaluate. Hence,

96^2 - 95^2 = (96-95)(96+95)
= (1)(191)
= 191

the answer is 191 :)

8 0

4 years ago

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P please please pa help ​

P please please pa help