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Darina [25.2K]
3 years ago
13

Can you help me with this

Mathematics
2 answers:
sashaice [31]3 years ago
7 0

Answer:

the answer is <u>30</u>

Step-by-step explanation:

-Dominant- [34]3 years ago
7 0

Answer:

your answer is 30

............

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A bike is 110inches long a motorcycle is 40% longer . How long is the motorcycle
Dmitry_Shevchenko [17]

Answer:

The motorcycle is 154inches long.

Step-by-step explanation:

the formula = part/whole=percent/100

x/110 = 40/100

x*100=110*40

x*100=4400

<u>x*100</u>=<u>4400</u>

100       100

x=44

The bike is 110inches long and the motorcycle is 40% longer all u have to do is add what we just got which was 44 to 110= 44+110=154.

Hope that made sense :)

5 0
3 years ago
Word problem for 3(23)
Flauer [41]
This shows the multiplication between 3 and 23. So your word problem will have to show that. Jean buys three packs of gum. Each pack has 23 pieces. How many pieces of gum does Jean have in total? :)
7 0
4 years ago
A survey shows that 45% of the respondents pick option A. Given that 50 people replied, what is the standard error of the propor
QveST [7]
The formula for the standard error is this:
σM = σ / √N

where
σM is the standard error
σ is the standard deviation
N is the number of samples

So,
σM = 0.45 / √50
σM = 0.0636 or 6.36%

The standard error is 0.0636
3 0
3 years ago
Read 2 more answers
CAN SOMEONE HELP MEE
shutvik [7]

Answer:

495 cm^2

Step-by-step explanation:

basically find the area of each shape,

rectangles: base x height

triangles: (base x height)/2

then add all the areas together

8 0
3 years ago
A bookstore classifies its books by reader group, type of book, and cost. What is the probability that a book selected at random
Murrr4er [49]

Answer:

Pr(Cb) & Pr(cost $15) = 15(Ncb)/(T1×T3)

Step-by-step explanation:

Classification of the book in to 3

First let's assign terms to each probability

Let:

T1= total number of type of Reader's group

T2 = total number of Type of book

T3 = total number of type of Cost

Probability of child's book and cost $15= Pr(Cb) & Pr(cost $15)

Then find probability of child's book and cost separately:

Pr of child's book = Pr(Cb)

Pr(Cb) = (number of child's book)/ total number of type of group

Ncb = number of child's book

Pr(Cb) = Ncb/T1

Pr (cost $15) = $15 book/total number of cost

Pr (cost $15) = 15/T3

probability of child's book and cost $15 = Pr(Cb) × Pr (cost $15)

= Ncb/T1 × 15/T3

Pr(Cb) & Pr(cost $15) = 15(Ncb)/(T1×T3)

3 0
3 years ago
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