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STALIN [3.7K]
3 years ago
5

Need help again, I really hate math please help​

Mathematics
1 answer:
hoa [83]3 years ago
3 0
C I think good luck
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A line passes through the point (4,-1) and (2,3)
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A triangular logo on the back of a T-shirt has a base of 51/2 inches and a height of 4 inches. What is the area of the logo?
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7 0
4 years ago
Darcy harvest 8 3/4 acres of corn every 5/6 of an hour. How many acres per hour?
otez555 [7]

Answer:

The answer is 10\frac{1}{2}\ per\ hour.

Step-by-step explanation:

Given:

Darcy harvest 8 3/4 acres of corn every 5/6 of an hour.

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Darcy harvest = 8\frac{3}{4}=\frac{35}{4}\ acres.

The time he took to harvest = \frac{5}{6}\ hour.

So, to get the acres per hour we put formula:

Distance = \frac{35}{4}\ acres.

Time=\frac{5}{6}\ hour.

Speed=\frac{distance}{time}

Speed=\frac{\frac{35}{4}}{\frac{5}{6}}

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3 0
4 years ago
A bag contain 3 black balls and 2 white balls.
Troyanec [42]

Answer:

Step-by-step explanation:

Total number of balls = 3 + 2 = 5

1)

a)

Probability \ of \ taking \ 2 \ black \ ball \ with \ replacement\\\\ = \frac{3C_1}{5C_1} \times \frac{3C_1}{5C_1} =\frac{3}{5} \times \frac{3}{5} = \frac{9}{25}\\\\

b)

Probability \ of \ one \ black \ and \ one\ white \ with \ replacement \\\\= \frac{3C_1}{5C_1} \times \frac{2C_1}{5C_1} = \frac{3}{5} \times \frac{2}{5} = \frac{6}{25}

c)

Probability of at least one black( means BB or BW or WB)

 =\frac{3}{5} \times \frac{3}{5} + \frac{3}{5} \times \frac{2}{5} + \frac{2}{5} \times \frac{3}{5} \\\\= \frac{9}{25} + \frac{6}{25} + \frac{6}{25}\\\\= \frac{21}{25}

d)

Probability of at most one black ( means WW or WB or BW)

=\frac{2}{5} \times \frac{2}{5} + \frac{3}{5} \times \frac{2}{5} \times \frac{2}{5} + \frac{3}{5}\\\\= \frac{4}{25} + \frac{6}{25} + \frac{6}{25}\\\\=\frac{16}{25}

2)

a) Probability both black without replacement

  =\frac{3}{5} \times \frac{2}{4}\\\\=\frac{6}{20}\\\\=\frac{3}{10}

b) Probability  of one black and one white

 =\frac{3}{5} \times \frac{2}{4}\\\\=\frac{6}{20}\\\\=\frac{3}{10}

c) Probability of at least one black ( BB or BW or WB)

 =\frac{3}{5} \times \frac{2}{4} + \frac{3}{5} \times \frac{2}{4} + \frac{2}{5} \times \frac{3}{4}\\\\=\frac{6}{20} + \frac{6}{20} + \frac{6}{20} \\\\=\frac{18}{20} \\\\=\frac{9}{10}

d) Probability of at most one black ( BW or WW or WB)

 =\frac{3}{5} \times \frac{2}{4} + \frac{2}{5} \times \frac{1}{4} + \frac{2}{5} \times \frac{3}{4}\\\\=\frac{6}{20} + \frac{2}{20} + \frac{6}{20} \\\\=\frac{14}{20}\\\\=\frac{7}{10}

6 0
3 years ago
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