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tekilochka [14]
4 years ago
10

2,5,8,11,14 write down in terms of n , an expression for the nth term for this sequence

Mathematics
1 answer:
Alisiya [41]4 years ago
4 0

Answer:

a_{n} = 3n - 1

Step-by-step explanation:

Note there is a common difference d between consecutive terms in the sequence, that is

5 - 2 = 8 - 5 = 11 - 8 = 14 - 11 = 3

This indicates the sequence is arithmetic with n th term

a_{n} = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 2 and d = 3, thus

a_{n} = 2 + 3(n - 1) = 2 + 3n - 3 = 3n - 1

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11. Kamala borrowed 26400 from a bank to buy a scooter at a rate of 15% per annum compounded yearly. What amount will she pay at
oee [108]
<h2>Answer </h2>

Amount (A) = P[1 + (r/100)]n

Principal (P) = ₹ 26400

Time period (n) = 2 years 4 months

Rate % (R) = 15% compounded annually

<h3>Steps </h3>

First, we will calculate Compound Interest (C.I) for the period of 2 years

A = P[1 + (r/100)]n

= 26400[1 + (15/100)]²

= 26400[(100/100) + (15/100)]²

= 26400 × 115/100 × 115/100

= 26400 × 23/20 × 23/20

= 26400 × 1.3225

= 34914

C.I. = A - P

= 34914 - 26400

= 8514

Now, we will find Simple Interest (S.I) for the period of 4 months

Principal for 4 months after C.I. for 2 years = ₹ 34,914

<h3>We know that ,</h3>

S.I = PRT/100

Here T = 4 months = 4/12 years = 1/3 years

S.I. for 4 months = (1/3) × 34914 × (15/100)

= (1/3) × 34914 × (3/20)

= 34914/20

= 1745.70

Total interest for 2 years 4 months = 8514 + 1745.70

= 10259.70

Total amount for 2 years 4 months = 26400 + 10259.70

= ₹ 36659.70

<h3>So , the correct answer is ₹ 36659.70 . </h3>

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