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yulyashka [42]
3 years ago
9

What is the solution to the system of

Mathematics
2 answers:
OverLord2011 [107]3 years ago
7 0
2x+2y=12.........&
6x-2y=20.........$

&+$: 8x=32
x=4

2*4+2y=12
y=4
Sonbull [250]3 years ago
3 0

Answer:

The solution, as an ordered pair, is (4, 2).

Step-by-step explanation:

2x + 2y = 12

6x - 2y = 20     Adding the 2 equations will eliminate y:

8x + 2y + (-2y) = 32

8x = 32

x = 4.

Substitute x = 4 in the first equation:

2(4) + 2y = 12

2y = 12 - 8

2y = 4

y = 2.

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Answer:

None, there are no degrees/exponents

Step-by-step explanation:

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3 years ago
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Determine the domain and range of (g ○ f)(x) if f of x is equal to 4 over the quantity x squared minus 4 end quantity and g(x) =
lara [203]

The domain and range of a function are the possible <em>x and y values </em>of the function.

<em>The domain and the range of the function is: (a) </em>\mathbf{D:\{x \in R|x \ne -2,2\}}<em> and </em>\mathbf{R:\{(-\infty,1) \cup (2,\infty)\}}<em />

The functions are given as:

\mathbf{f(x) = \frac{4}{x^2 - 4}}

\mathbf{g(x) = x + 2}

(g o f)(x) is calculated as:

\mathbf{(g\ o\ f)(x) = g(f(x))}

So, we have:

\mathbf{(g\ o\ f)(x) = \frac{4}{x^2 - 4} + 2}

Take LCM

\mathbf{(g\ o\ f)(x) = \frac{4 + 2x^2 - 8}{x^2 - 4} }

\mathbf{(g\ o\ f)(x) = \frac{2x^2 - 4}{x^2 - 4} }

Represent the denominator as follows, to calculate the domain

\mathbf{x^2 - 4 \ne 0 }

Add 4 to both sides

\mathbf{x^2 \ne 4 }

Take square roots of bot sides

\mathbf{x \ne \±2 }

Hence, the domain of the function is:

\mathbf{D:\{x \in R|x \ne -2,2\}}

On the graph of \mathbf{(g\ o\ f)(x) = \frac{2x^2 - 4}{x^2 - 4} } (see attachment), the function does not have a value from <em>y = 1 to 2.</em>

Hence, the range is:

\mathbf{R:\{(-\infty,1) \cup (2,\infty)\}}

Read more about domain and range at:

brainly.com/question/1632425

5 0
2 years ago
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marishachu [46]
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7 0
4 years ago
CAN SOMEONE HELP ME WITH THIS PLEASE AND THANK YOU.
Mariana [72]

Answer:

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8 0
3 years ago
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