the parallel line is 2x+5y+15=0.
Step-by-step explanation:
ok I hope it will work
soo,
Solution
given,
given parallel line 2x+5y=15
which goes through the point (-10,1)
now,
let 2x+5y=15 be equation no.1
then the line which is parallel to the equation 1st
2 x+5y+k = 0 let it be equation no.2
now the equation no.2 passes through the point (-10,1)
or, 2x+5y+k =0
or, 2*-10+5*1+k= 0
or, -20+5+k= 0
or, -15+k= 0
or, k= 15
putting the value of k in equation no.2 we get,
or, 2x+5y+k=0
or, 2x+5y+15=0
which is a required line.
Answer:
The slope is -5x
Step-by-step explanation:
To find the slope, you do rise/run. So to get from one point to the other, you would move 5 units down, and 1 unit to the right.
It can be written as -5/1 or -5.
Hope this helps!
Answer:
Step-by-step explanation:
Given
See attachment
Required
Explain and correct the error
The error in the equation is that: the formula of cosine of angle A is used to calculate the sine of angle A.
The ratio can be corrected as by using:
Answer:
d a m i dont even know this
Step-by-step explanation:
