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Natali [406]
3 years ago
9

Can someone help me with this 5 question quiz?

Mathematics
1 answer:
zavuch27 [327]3 years ago
8 0
X= (-40,0)
y= (0,15)
May God bless you and your family
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The mean amount spent by a family of four on food per month is $500 with a standard deviation of $75. Assuming that the food cos
JulijaS [17]

Answer:

The probability that a family spends less than $410 per month

P( X < 410) = 0.1151

Step-by-step explanation:

<u><em>Step(i):-</em></u>

<em>Given mean of the population = 500 </em>

<em>Given standard deviation of the Population = 75</em>

Let 'X' be the variable in normal distribution

      Z = \frac{x-mean}{S.D}

<em>Given X = $410</em>

<em></em>Z = \frac{410-500}{75} = - 1.2<em></em>

<u><em>Step(ii):-</em></u>

The probability that a family spends less than $410 per month

P( X < 410) = P( Z < - 1.2 )

                  =  0.5 - A( -1.2)

                 = 0.5 - A(1.2)

                = 0.5 - 0.3849  ( ∵from normal table)

                = 0.1151

<u>Final answer:-</u>

The probability that a family spends less than $410 per month

P( X < 410) = 0.1151

6 0
3 years ago
Can u help me please better picture
gladu [14]

Hi, there.

For this question, we can apply the Pythagorean theorem a^2 + b^2 = c^2.

I'm sure you've seen this equation before, and they kind of tried to trip you up with this problem. Trust me, it's easier than it looks. Let's break it down.

Lengths a and b both have the value of 48, which means that the value s in \sqrt{2s^2} is 48, because the length of the hypotenuse is the same as the length and height squared multiplied by 2.

Plug in the value for c: a^2 + b^2 = (\sqrt{2s^2})^2

Plug in the value for s:

(\sqrt{2(48^2)})^2

Do the innermost exponents first:

(\sqrt{2(2304)})^2

The square root symbol and the power of 2 cancel each other out, so we are left with:

s = 2(2304), so the hypotenuse is 4608 inches.

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3 years ago
Whats 952.80 ↪ hundreds​
Kazeer [188]

Answer:

952

Step-by-step explanation:

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you have 5 apples now

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your answer is D.        hope this helped

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