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3 years ago

Please help me to solve the 7th part !

Mathematics

1 answer:

pashok25 [27]3 years ago

4 0

Answer:

i don't know

Step-by-step explanation:

sorry sorry sorry berry much

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Which functions have a maximum and are transformed to the left and down of the parent function, f(x)=x2? Check

KATRIN_1 [288]

Using translation concepts, the functions that have a maximum and are transformed to the left and down of the parent function are given by:

g(x) = -5(x + 10)² - 1

t(x) = -2x² - 4x - 3

<h3>What is a translation?</h3>

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction in it's definition.

For the translations, we have that:

Shift left, hence x -> x + a, a > 0.

Shift down, hence y -> y - a, a > 0.

Having a maximum means that the leading coefficient is negative.

The functions that respect these conditions are:

g(x) = -5(x + 10)² - 1

t(x) = -2x² - 4x - 3 = -2(x² + 2x) - 3 = -2(x + 1)² - 1

More can be learned about translation concepts at brainly.com/question/4521517

#SPJ1

8 0

2 years ago

Y^3-8y^2+19y=12<br>Solve

Sliva [168]

Answer:

Step-by-step explanation:

steps are below

step 1

y^3-8y^2+19y=12 equation

step 2

y^3-8y2+19y(-12)=12(-12) minus 12 from both sides

y^3-8y^2+19y-12=0

step 3

(y-1)(y-3)(y-4)=0 add brackets

step 4

(y-1)(y-3)(y-4)=0 factor

step 5

y-1=0 or y−3=0 or y-4=0 set them equal

Answer:

y=1 or y=3 or y=4

3 0

3 years ago

The sum of 2 numbers is 100. Twice the first number plus twice the second number is 200. What are the numbers?

dlinn [17]

Answer:

50+50=100

100+100=200

Step-by-step explanation:

The sum of 2 numbers is 100. 50 x 2 = 100

Twice the first number plus twice the second number is 200.

50+50=100 so therfore 100+100 makes 200

6 0

3 years ago

Read 2 more answers

Is 1/4 the answer to this what ratio forms a porportion with 8/36

Svetlanka [38]

No.
1/4 would be proportional to 9/36.

8/36 can be simplified to 4/18, and further reduced to 2/9.

3 0

3 years ago

Suppose the number of children in a household has a binomial distribution with parameters n=12n=12 and p=50p=50%. Find the proba

nadya68 [22]

Answer:

a) 20.95% probability of a household having 2 or 5 children.

b) 7.29% probability of a household having 3 or fewer children.

c) 19.37% probability of a household having 8 or more children.

d) 19.37% probability of a household having fewer than 5 children.

e) 92.71% probability of a household having more than 3 children.

Step-by-step explanation:

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

In this problem, we have that:

$n = 12, p = 0.5$

(a) 2 or 5 children

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{12,2}.(0.5)^{2}.(0.5)^{10} = 0.0161$

$P(X = 5) = C_{12,5}.(0.5)^{5}.(0.5)^{7} = 0.1934$

$p = P(X = 2) + P(X = 5) = 0.0161 + 0.1934 = 0.2095$

20.95% probability of a household having 2 or 5 children.

(b) 3 or fewer children

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{12,0}.(0.5)^{0}.(0.5)^{12} = 0.0002$

$P(X = 1) = C_{12,1}.(0.5)^{1}.(0.5)^{11} = 0.0029$

$P(X = 2) = C_{12,2}.(0.5)^{2}.(0.5)^{10} = 0.0161$

$P(X = 3) = C_{12,3}.(0.5)^{3}.(0.5)^{9} = 0.0537$

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.0002 + 0.0029 + 0.0161 + 0.0537 = 0.0729$

7.29% probability of a household having 3 or fewer children.

(c) 8 or more children

$P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 8) = C_{12,8}.(0.5)^{8}.(0.5)^{4} = 0.1208$

$P(X = 9) = C_{12,9}.(0.5)^{9}.(0.5)^{3} = 0.0537$

$P(X = 10) = C_{12,10}.(0.5)^{10}.(0.5)^{2} = 0.0161$

$P(X = 11) = C_{12,11}.(0.5)^{11}.(0.5)^{1} = 0.0029$

$P(X = 12) = C_{12,12}.(0.5)^{12}.(0.5)^{0} = 0.0002$

$P(X \geq 8) = P(X = 8) + P(X = 9) + P(X = 10) + P(X = 11) + P(X = 12) = 0.1208 + 0.0537 + 0.0161 + 0.0029 + 0.0002 = 0.1937$

19.37% probability of a household having 8 or more children.

(d) fewer than 5 children

$P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)$

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{12,0}.(0.5)^{0}.(0.5)^{12} = 0.0002$

$P(X = 1) = C_{12,1}.(0.5)^{1}.(0.5)^{11} = 0.0029$

$P(X = 2) = C_{12,2}.(0.5)^{2}.(0.5)^{10} = 0.0161$

$P(X = 3) = C_{12,3}.(0.5)^{3}.(0.5)^{9} = 0.0537$

$P(X = 4) = C_{12,4}.(0.5)^{4}.(0.5)^{8} = 0.1208$

$P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.0002 + 0.0029 + 0.0161 + 0.0537 + 0.1208 = 0.1937$

19.37% probability of a household having fewer than 5 children.

(e) more than 3 children

Either a household has 3 or fewer children, or it has more than 3. The sum of these probabilities is 100%.

From b)

7.29% probability of a household having 3 or fewer children.

p + 7.29 = 100

p = 92.71

92.71% probability of a household having more than 3 children.

5 0

3 years ago

Please help me to solve the 7th part !​

Please help me to solve the 7th part !