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antoniya [11.8K]
2 years ago
13

macey bought 11 apple pies at the bakery. she wants to give each of her 4 friends equal amounts of pie how much will each friend

get
Mathematics
2 answers:
just olya [345]2 years ago
8 0

Answer:

each friend would get 2 3/4

Step-by-step explanation:

11/4

Sauron [17]2 years ago
4 0

Answer:

her friends will get 2.75

Step-by-step explanation:

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Step-by-step explanation:

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Given that f(x) = x^2 – 2x - 63 and g(x) = x + 7, find (f - g)(x)
Juliette [100K]

Answer:

(f - g)(x) = x² - 3x - 70

General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Distributive Property

<u>Algebra I</u>

  • Combining Like Terms

Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = x² - 2x - 63

g(x) = x + 7

(f - g)(x) is f(x) - g(x)

<u>Step 2: Find (f - g)(x)</u>

  1. Substitute:                               (f - g)(x) = x² - 2x - 63 - (x + 7)
  2. Distribute -1:                            (f - g)(x) = x² - 2x - 63 - x - 7
  3. Combine like terms (x):          (f - g)(x) = x² - 3x - 63 - 7
  4. Combine like terms (Z):          (f - g)(x) = x² - 3x - 70
3 0
2 years ago
Describe the steps to dividing imaginary numbers and complex numbers with two terms in the denominator?
zlopas [31]

Answer:

Let be a rational complex number of the form z = \frac{a + i\,b}{c + i\,d}, we proceed to show the procedure of resolution by algebraic means:

1) \frac{a + i\,b}{c + i\,d}   Given.

2) \frac{a + i\,b}{c + i\,d} \cdot 1 Modulative property.

3) \left(\frac{a+i\,b}{c + i\,d} \right)\cdot \left(\frac{c-i\,d}{c-i\,d} \right)   Existence of additive inverse/Definition of division.

4) \frac{(a+i\,b)\cdot (c - i\,d)}{(c+i\,d)\cdot (c - i\,d)}   \frac{x}{y}\cdot \frac{w}{z} = \frac{x\cdot w}{y\cdot z}  

5) \frac{a\cdot (c-i\,d) + (i\,b)\cdot (c-i\,d)}{c\cdot (c-i\,d)+(i\,d)\cdot (c-i\,d)}  Distributive and commutative properties.

6) \frac{a\cdot c + a\cdot (-i\,d) + (i\,b)\cdot c +(i\,b) \cdot (-i\,d)}{c^{2}-c\cdot (i\,d)+(i\,d)\cdot c+(i\,d)\cdot (-i\,d)} Distributive property.

7) \frac{a\cdot c +i\,(-a\cdot d) + i\,(b\cdot c) +(-i^{2})\cdot (b\cdot d)}{c^{2}+i\,(c\cdot d)+[-i\,(c\cdot d)] +(-i^{2})\cdot d^{2}} Definition of power/Associative and commutative properties/x\cdot (-y) = -x\cdot y/Definition of subtraction.

8) \frac{(a\cdot c + b\cdot d) +i\cdot (b\cdot c -a\cdot d)}{c^{2}+d^{2}} Definition of imaginary number/x\cdot (-y) = -x\cdot y/Definition of subtraction/Distributive, commutative, modulative and associative properties/Existence of additive inverse/Result.

Step-by-step explanation:

Let be a rational complex number of the form z = \frac{a + i\,b}{c + i\,d}, we proceed to show the procedure of resolution by algebraic means:

1) \frac{a + i\,b}{c + i\,d}   Given.

2) \frac{a + i\,b}{c + i\,d} \cdot 1 Modulative property.

3) \left(\frac{a+i\,b}{c + i\,d} \right)\cdot \left(\frac{c-i\,d}{c-i\,d} \right)   Existence of additive inverse/Definition of division.

4) \frac{(a+i\,b)\cdot (c - i\,d)}{(c+i\,d)\cdot (c - i\,d)}   \frac{x}{y}\cdot \frac{w}{z} = \frac{x\cdot w}{y\cdot z}  

5) \frac{a\cdot (c-i\,d) + (i\,b)\cdot (c-i\,d)}{c\cdot (c-i\,d)+(i\,d)\cdot (c-i\,d)}  Distributive and commutative properties.

6) \frac{a\cdot c + a\cdot (-i\,d) + (i\,b)\cdot c +(i\,b) \cdot (-i\,d)}{c^{2}-c\cdot (i\,d)+(i\,d)\cdot c+(i\,d)\cdot (-i\,d)} Distributive property.

7) \frac{a\cdot c +i\,(-a\cdot d) + i\,(b\cdot c) +(-i^{2})\cdot (b\cdot d)}{c^{2}+i\,(c\cdot d)+[-i\,(c\cdot d)] +(-i^{2})\cdot d^{2}} Definition of power/Associative and commutative properties/x\cdot (-y) = -x\cdot y/Definition of subtraction.

8) \frac{(a\cdot c + b\cdot d) +i\cdot (b\cdot c -a\cdot d)}{c^{2}+d^{2}} Definition of imaginary number/x\cdot (-y) = -x\cdot y/Definition of subtraction/Distributive, commutative, modulative and associative properties/Existence of additive inverse/Result.

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2 years ago
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