Let first number = X and 2nd number = Y
Equation 1: 5X + 8Y = -13
Equation 2: 5X + 10Y = -15
Multiply equation 1 by -1 to get: -5X + -8Y = 13
Now add the 2 equations together:
-5X + 5X = 0
-8Y + 10Y = 2Y
13 + -15 = -2
The total of the 2 equations is 2Y = -2
divide both sides by 2 to solve for Y
Y = -2 / 2
Y = -1
Now we know the 2nd number is -1, so replace Y in the 1st equation and solve for X
5X +8(-1) = -13
5x + -8 = -13
Add 8 to both sides:
5x = -5
Divide both sides by 5 to get x
X = -5 / 5
X = -1
Both numbers are -1
To check replace X and Y with -1 and solve:
1st equation: 5(-1) +8(-1) = -5 + -8 = -13 TRUE
2nd equation: 5(-1) +10(-1) = -5 + -10 = -15 TRUE
Both numbers are -1
Given:
1st fraction - 7/24
2nd fraction - 34/48
Rules in dividing fractions:
1) Get the reciprocal of the 2nd fraction.
34/48 becomes 48/34
2) Multiply the 1st fraction to the reciprocal of the 2nd fraction
7/24 * 48/34 = 7*48 / 24*34 = 336/816
3) Simplify the fraction
336/816 ⇒ 112/272 ⇒ 56/136 ⇒ 14/34 ⇒ 7/17
336 ÷ 3 = 112
816 ÷ 3 = 272
112 ÷ 2 = 56
272 ÷ 2 = 136
56 ÷ 4 = 14
136 ÷ 4 = 34
14 ÷ 2 = 7
34 ÷ 2 = 17
7/24 ÷ 35/48 = 7/17
I think the answer is fjeiksjdowkanxeiwjsfiriwijzhcjqokXjdiwoaijxd
Answer:
<h2>The distance from the pitcher's mound and to second base is 37.99 approximately.</h2>
Step-by-step explanation:
The diamond is a square, which in this case has 50 feet long each side, and from home to pitcher is 38 feet. Notice that home is a vertex of the square and the pitcher's mound is the intersection of the diagonals, where they cut half.
We can find the distance from the pitcher to first base using Pythagorean's Theorem, where 50 feet is the hypothenuse.
Therefore, the distance from the pitcher to first base is 32.5 feet, approximately.
Now, we can use again Pythagorean's Theorem to find the distance from pitcher to second base, where the hypothenuse is 50 feet.
Therefore, the distance from the pitcher's mound and to second base is 37.99 approximately.
<em>(this results make sense, because the diagonals of a square intersect at half, that means all bases have the same distance from pitcher's mound, so the second way to find the distance asked in the question is just using theory)</em>
Using the identity :
Cos (2a) = 1-2 Sin^2(a)
Therefore :<span>1−2 sin ^2 (22.5∘) = Cos(2a)
= Cos (2 * 22.5) = Cos 45</span>
