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Aneli [31]
3 years ago
14

Krupton (Kr) is a A. GasB. MetalC. Non of theseD. Metalloid​

Chemistry
1 answer:
Katarina [22]3 years ago
3 0
B is gas


The chemical element krypton is classed as a noble gas and a nonmetal.







Love you
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If the molar heat of fusion of water is 6.01
Zolol [24]

Answer : The heat energy required to melt 2 kg of ice was, 667.7 kJ

Explanation :

First we have to calculate the moles of ice.

\text{Moles of ice}=\frac{\text{Given mass ice}}{\text{Molar mass ice}}=\frac{2kg}{18g/mol}=\frac{2000g}{18g/mol}=111.1mol

Now we have to calculate the heat energy.

As, heat energy required to melt 1 mole of ice = 6.01 kJ

So, heat energy required to melt 111.1 mole of ice = 111.1 × 6.01 kJ

                                                                                  = 667.7 kJ

Therefore, the heat energy required to melt 2 kg of ice was, 667.7 kJ

6 0
4 years ago
A student investigated the diffusion of ammonia gas, NH3, and hydrogen chloride gas, HCl. The damp red litmus paper for NH3 chan
Alex Ar [27]

Answer:

43.96secs

Explanation:

M1 = molar mass of NH3 = 14 + (3x1) = 14 + 3 = 17g/mol

t1 = time for NH3 to diffuse = 30secs

M2 = molar mass of HCl = 1 + 35.5 = 36.5g/mol

t2 = time for HCl to diffuse =?

From Graham's law of diffusion:

t2/t1 = √(M2/M1)

t2/30 = √(36.5/17)

t2/30 = 1.465

Cross multiply

t2 = 30 x 1.465

t2 = 43.96secs

Therefore it will take 43.96secs for the damp blue litmus paper to change colour for HCl.

8 0
3 years ago
Mario uses a hot plate to heat a beaker of 50mL of water. He used a thermometer to measure the temperature of the water. The wat
Alex777 [14]

Answer:

The boiling point decreases as the volume decreases.

Explanation:

The Temperature - Volume law otherwise called as Charles law is applied, which says that the volume of the given gas at constant pressure is directly proportional to the temperature measured in Kelvin. As the volume increases, the temperature also increases, if the volume decreases, then the temperature also decreases.

As per the Charles law, here the volume is decreased from 50 ml to 25 ml so the boiling point also decreases.

8 0
3 years ago
Read 2 more answers
Q2: A compound consists of 40.00 % C, 6.67 % H and
balandron [24]

Answer:

C6H12O6

Explanation:

Just use the table method like I did and compared the molecular mass with the mass of the empirical formula.

6 0
3 years ago
Una masa de aire ocupa un volumen de5litro a una temperatura de 120c Cual será el nuevo volumen si la temperatura se reduce ala
zalisa [80]

Answer:

1. V_2=2.5L

2. V_2=8000mL

3. V_2=176.3L

Explanation:

¡Hola!

En este caso, dada la información para estos problemas, procedemos de la siguiente manera, basado en las leyes de los gases ideales:

1. Una masa de aire ocupa un volumen de 5 litros a una temperatura de 120 °C Cual será el nuevo volumen si la temperatura se reduce a la mitad:

Aqui, utilizamos la ley de Charles, asegurándonos que la temperatura está en Kelvin:

\frac{T_2}{V_2} =\frac{T_1}{V_1} \\\\V_2 =\frac{V_1T_2}{T_1} \\\\V_2 =\frac{5L*196.5K}{393K} \\\\V_2=2.5L

2. Un gas ideal ocupa un volumen de 4000 ml a una presión absoluta de 1500 kilo pascal Cual será la presión si el gas es comprimido lentamente hasta 750 kilo pascal a temperatura constante?

Aquí, utilizamos la ley de Boyle, dado que la temperatura se mantiene constante, calculando el volumen, ya que lo que se da es la presión final:

\neq P_2V_2=P_1V_1\\\\V_2=\frac{P_1V_1}{P_2}\\\\ V_2=\frac{4000mL*1500kPa}{750kPa}\\\\V_2=8000mL

3. Un gas ocupa un volumen de 200 litros a 95°C y 782 mmHg Cual será el volumen ocupado por dicho gas a 65°C y 815 mmHg:

Aquí, utilizamos la ley combinada de los gases ideales, asegurándonos que las temperaturas están en Kelvin:

\frac{T_2}{P_2V_2} =\frac{T_1}{P_1V_1} \\\\V_2 =\frac{P_1V_1T_2}{P_2T_1} \\\\V_2 =\frac{782mmHg*200L*338K}{815mmHg*368K}\\\\V_2=176.3L

¡Saludos!

6 0
3 years ago
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