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3 years ago

< Question 3 of 25

Chemistry

1 answer:

Nonamiya [84]3 years ago

5 0

The answer is 360ms I hope this helps

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John placed a number of small stones into a plastic container of water and froze it. Stay what kind of mixture john has

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Think, does a chemical reaction take place? Do the rocks and/or the water undergo any chemical changes?

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3 years ago

Write a balanced equation for the neutralization reaction between the following (you do not need to include states of matter):

givi [52]

Answer:

Both have the same balance on a weight with. 2 dimensional figures on the area formula

Explanation:

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2 years ago

Be sure to answer all parts. Consider the formation of ammonia in two experiments. (a) To a 1.00−L container at 727°C, 1.30 mol

Sonbull [250]

Answer: The value of $K_c$ for $2NH_3(g)\rightleftharpoons N_2(g)+3H_2(g)$ reaction is $5.13\times 10^2$

Explanation:

We are given:

Initial moles of nitrogen gas = 1.30 moles

Initial moles of hydrogen gas = 1.65 moles

Equilibrium moles of ammonia = 0.100 moles

Volume of the container = 1.00 L

For the given chemical equation:

$N_2(g)+3H_2(g)\rightleftharpoons 2NH_3(g)$

Initial: 1.30 1.65

At eqllm: 1.30-x 1.65-3x 2x

Evaluating the value of 'x'

$\Rightarrow 2x=0.100\\\\\Rightarrow x=0.050mol$

The expression of $K_c$ for above equation follows:

$K_c=\frac{[NH_3]^2}{[N_2]\times [H_2]^3}$

Equilibrium moles of nitrogen gas = $(1.30-x)=(1.30-0.05)=1.25mol$

Equilibrium moles of hydrogen gas = $(1.65-x)=(1.65-0.05)=1.60mol$

Putting values in above expression, we get:

$K_c=\frac{(0.100)^2}{1.25\times (1.60)^3}\\\\K_c=1.95\times 10^{-3}$

Calculating the $K_c'$ for the given chemical equation:

$2NH_3(g)\rightleftharpoons N_2(g)+3H_2(g)$

$K_c'=\frac{1}{K_c}\\\\K_c'=\frac{1}{1.95\times 10^{-3}}=5.13\times 10^2$

Hence, the value of $K_c$ for $2NH_3(g)\rightleftharpoons N_2(g)+3H_2(g)$ reaction is $5.13\times 10^2$

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3 years ago

Read 2 more answers

Why is isn’t it chemical change if you mixed paint together?

VashaNatasha [74]

There is no chemical change

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3 years ago

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What number of moles of Pb (NO3)2 is consumed when 54 g of KNO3 is produced

Ivenika [448]

Explanation:

hope it helps you understand moles

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3 years ago