<u>Answer:</u> The molarity of the stock solution is 4.64 M
<u>Explanation:</u>
To calculate the molarity of the diluted solution, we use the equation:
where,
are the molarity and volume of the stock solution
are the molarity and volume of diluted solution
We are given:
Putting values in above equation, we get:

Hence, the molarity of the stock solution is 4.64 M
Answer:
See explanation and image attached
Explanation:
Aromatic hydrocarbons undergo electrophillic substitution. Usually, substituted benzene is more or less reactive to electrophillic substitution compared to unsubstituted benzene.
Substituents on the benzene ring tend to direct the incoming electrophile during electrophillic substititution. The presence of the -CH3 group on toluene directs the incoming Br electrophile to the ortho/para position.
Where the incoming electrphile E is Bromine, we can see that in the ortho/ para product, the electron pushing -CH3 stabilizes the resonance structure formed and increases electron density at the ortho/para position via resonance compared to the meta product as we can see from the image attached. Hence, the ortho and para products predominate over meta products.
Image credit: Chemistry steps
Answer:
I would say D (not sure tho)
Explanation:
The molar mass of monotonic Nitrogen is 14 g/mol. Since this is diatomic Nitrogen, double that to 28 g/mol.
Next, divide total mass by molar mass, 500 g / 28 g/mol, which gives <span>17.8571 moles. A mole is defined as being 6.022*10^23 molecules, so multiply moles by molecules/mol (Avogadro's number), and we finally end up with something like 1.075 * 10^25, give or take a few billion particles.</span>