Answer:

Step-by-step explanation:
The unit vector for a nonzero vector, say u, in the direction of u is given by:
û =
---------------(i)
Where;
|u| = magnitude of vector u
From the question;
u = (4, -4)
First let's calculate the magnitude of u as follows;
|u| = 
|u| = 
|u| =
= 
Now, substitute u and |u| into equation (i) as follows;
û = 
û = 
û = 
Therefore, the unit vector is 
The value of the
and
are 0 and 1.153 .
<h3>
</h3><h3>
What is the limiting value of a function?</h3>
Limiting Value of a Function. The function's limit is the value of the function as its independent variable, such as x approaches a certain value called the limiting value. For simple equations, this is similar to finding out the value of y when x has a unique value.
Given that,
f(x) = 
First to calculate the limit value of the given function at x=0.
= 
= 4×0×1 (∵ cos0 = 1)
= 0
Similarly,
= 
= 4×
×cos
= 4×
×
(∵cos60° =
)
= 1.153
Hence, The value of the
and
are 0 and 1.153.
To learn more about the limit of the function from the given link:
brainly.com/question/23935467
#SPJ9
Answer:
Quadratic
Step-by-step explanation:
A linear equation is just a line and an exponential function goes in the same direction
A quadratic us a parabola which has a turning point
4, 12, and 18 in two different ways
<span>(4 + 12) + 18 = 16 + 18 = 34
4 + (12 + 18) = 4 + 30 = 34
answer is B) </span><span>(4 + 12) + 18 = 16 + 18 = 34; 4 + (12 + 18) = 4 + 30 = 34 (second choice)</span>
Answer:
it will be broken into 9*what ever x is
Hope This Helps!!!