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jonny [76]
3 years ago
14

there are 22 animals in the barn. Some are chickens and some are pigs . There are 74 legs in all. How many of each animal are th

ere.show your work​
Mathematics
1 answer:
pshichka [43]3 years ago
4 0

Answer: 8ry73407858rgiebdkljsh98weyr89p3yw2pr98y32 98ryweuidhiusehfp9823y[0=e0=9iOK'D;LKp0i92e0238r0823ur9843y09`u`09`[udw'jld'lajf[0i=i=09iwepoi======    . klnoijoj/

Step-by-step explanation: WHAT KINNNDA QUESTION IS DIS

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Parker wants to ride his bicycle 34 miles this week. He has already ridden 10 miles. If he rides for 5 more days, how many miles
vazorg [7]

Answer: He rode 4.8 miles each day.

Variable: x = Constant distance distance traveledd each day.

Equation : 10+5x=34

Step-by-step explanation:

Total distance needs to travel = 34 miles

Distance already traveled = 10 miles

He will ride bicycle for 5  more days.

Let x = Constant distance distance traveledd each day.

Total distance = 10+5x

i.e.

10+5x=34\\\\\Rightarrow\ 5x=24\\\\\Rightarrow\ x=4.8

Hence, he rode 4.8 miles each day.

7 0
3 years ago
Evaluate the expression (-7) to the power of 3
Goshia [24]
-343 I think but I am not totally sure
3 0
3 years ago
Read 2 more answers
Which pair of numbers has a lcm of 12<br> 1 and 6<br> 2 and 3<br> 2 and 6<br> 3 and 4
Nana76 [90]

Answer:

3 and 4

and

2 and 6

Step-by-step explanation:

3×4=12

2×6=12

3 0
3 years ago
Read 2 more answers
The point P(-6, -6) is reflected over the x-axis. What are the coordinates of the resulting
Fed [463]

Answer:

It would be (6,-6)

Step-by-step explanation:

Hope this helps.

7 0
3 years ago
Please help me to prove this!​
Sophie [7]

Answer:  see proof below

<u>Step-by-step explanation:</u>

Given: A + B = C                → A = C - B

                                          → B = C - A

Use the Double Angle Identity:     cos 2A = 2 cos² A - 1

                                             → (cos 2A + 1)/2 = cos² A

Use Sum to Product Identity: cos A + cos B = 2 cos [(A + B)/2] · 2 cos [(A - B)/2]

Use Even/Odd Identity: cos (-A) = cos (A)

<u>Proof LHS → RHS:</u>

LHS:                     cos² A + cos² B + cos² C

\text{Double Angle:}\qquad \dfrac{\cos 2A+1}{2}+\dfrac{\cos 2B+1}{2}+\cos^2 C\\\\\\.\qquad \qquad \qquad =\dfrac{1}{2}\bigg(2+\cos 2A+\cos 2B\bigg)+\cos^2 C\\\\\\.\qquad \qquad \qquad =1+\dfrac{1}{2}\bigg(\cos 2A+\cos 2B\bigg)+\cos^2 C

\text{Sum to Product:}\quad 1+\dfrac{1}{2}\bigg[2\cos \bigg(\dfrac{2A+2B}{2}\bigg)\cdot \cos \bigg(\dfrac{2A-2B}{2}\bigg)\bigg]+\cos^2 C\\\\\\.\qquad \qquad \qquad =1+\cos (A+B)\cdot \cos (A-B)+\cos^2 C

\text{Given:}\qquad \qquad 1+\cos C\cdot \cos (A-B)+\cos^2C

\text{Factor:}\qquad \qquad 1+\cos C[\cos (A-B)+\cos C]

\text{Sum to Product:}\quad 1+\cos C\bigg[2\cos \bigg(\dfrac{A-B+C}{2}\bigg)\cdot \cos \bigg(\dfrac{A-B-C}{2}\bigg)\bigg]\\\\\\.\qquad \qquad \qquad =1+2\cos C\cdot \cos \bigg(\dfrac{A+(C-B)}{2}\bigg)\cdot \cos \bigg(\dfrac{-B-(C-A)}{2}\bigg)

\text{Given:}\qquad \qquad =1+2\cos C\cdot \cos \bigg(\dfrac{A+A}{2}\bigg)\cdot \cos \bigg(\dfrac{-B-B}{2}\bigg)\\\\\\.\qquad \qquad \qquad =1+2\cos C \cdot \cos A\cdot \cos (-B)

\text{Even/Odd:}\qquad \qquad 1+2\cos C \cdot \cos A\cdot \cos B\\\\\\.\qquad \qquad \qquad \quad =1+2\cos A \cdot \cos B\cdot \cos C

LHS = RHS: 1 + 2 cos A · cos B · cos C = 1 + 2 cos A · cos B · cos C   \checkmark

5 0
3 years ago
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