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2 years ago

Use the information for the question below.

Mathematics

1 answer:

Zielflug [23.3K]2 years ago

7 0

Answer:

The correct option is d. Project B.

Step-by-step explanation:

Note: See the attached excel file for the calculation of the Cumulative Cash Flows of Projects A and B.

Payback period refers to the number of time or period that is needed to recoup the amount of money spent a project. The

payback period rule states that when considering two or more projects, a project with the shortest payback period should be selected.

Payback period can be calculated as follows:

Payback period = Time before full recovery + (Unrecovered cost at start of the time of full recovery / Cash flow during the time of full recovery) ………………. (1)

Using the information in the excel file (in red color), equation (1) can be calculated for Project A and Project B as follows:

Project A payback period = 2 + ($1,000 / $3,000) = 2.33

Project B payback period = 2 + ($3,000 / $10,000) = 2.30

Since the payback period of Project B payback period which is 2.30 is lower than the Project A payback period of 2.33, Project B should be selected.

Therefore, the correct option is d. Project B.

Download xlsx

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Answer:

$y_p=A+Bt+Ce^{2t}$

Step-by-step explanation:

Given: $y'' - 2y' = 6t + 5e^{2t}$ .

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A first order differential equation $\frac{\mathrm{d} y}{\mathrm{d} x}=f\left ( x,y \right )$ is said to be homogeneous if $f(tx,ty)=f(x,y)$ for all t.

Consider homogeneous equation $y''-2y'=0$

Let $y=e^{rt}$ be the solution .

We get $(r^2-2r)e^{rt}=0$

Since $e^{rt}\neq 0$ , $r^2-2r=0$ .

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As constant term and $e^{2t}$ are already in the R.H.S of equation

$y" - 2y' = 6t + 5e^{2t}$ , we can take $y_p$ as $y_p=A+Bt+Ce^{2t}$

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3 years ago

Given right triangle jkl, what is the value of cos(l)? five-thirteenths five-twelfths twelve-thirteenths twelve-fifths

kykrilka [37]

The value of the cosine ratio cos(L) is 5/13

<h3>How to determine the cosine ratio?</h3>

The complete question is added as an attachment

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Evaluate the exponent

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h = 13

The cosine ratio is then calculated as:

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This gives

cos(L) =5/13

Hence, the value of the cosine ratio cos(L) is 5/13

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1 year ago

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3 years ago

What is the sum of the following infinite series?<br> 5+ 15/7 + 45/49 + 135/343

liberstina [14]

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3 years ago

Please help :)))) ( attachment )

Anastaziya [24]

Let,
f(x) = -2x+34
g(x) = (-x/3) - 10
h(x) = -|3x|
k(x) = (x-2)^2

This is a trial and error type of problem (aka "guess and check"). There are 24 combinations to try out for each problem, so it might take a while. It turns out that

g(h(k(f(15)))) = -6
f(k(g(h(8)))) = 2

So the order for part A should be: f, k, h, g
The order for part B should be: h, g, k f
note how I'm working from the right and moving left (working inside and moving out).

Here's proof of both claims

-----------------------------------------

Proof of Claim 1:

f(x) = -2x+34
f(15) = -2(15)+34
f(15) = 4
-----------------
k(x) = (x-2)^2
k(f(15)) = (f(15)-2)^2
k(f(15)) = (4-2)^2
k(f(15)) = 4
-----------------
h(x) = -|3x|
h(k(f(15))) = -|3*k(f(15))|
h(k(f(15))) = -|3*4|
h(k(f(15))) = -12
-----------------
g(x) = (-x/3) - 10
g(h(k(f(15))) ) = (-h(k(f(15))) /3) - 10
g(h(k(f(15))) ) = (-(-12) /3) - 10
g(h(k(f(15))) ) = -6

-----------------------------------------

Proof of Claim 2:

h(x) = -|3x|
h(8) = -|3*8|
h(8) = -24
---------------
g(x) = (-x/3) - 10
g(h(8)) = (-h(8)/3) - 10
g(h(8)) = (-(-24)/3) - 10
g(h(8)) = -2
---------------
k(x) = (x-2)^2
k(g(h(8))) = (g(h(8))-2)^2
k(g(h(8))) = (-2-2)^2
k(g(h(8))) = 16
---------------
f(x) = -2x+34
f(k(g(h(8))) ) = -2*(k(g(h(8))) )+34
f(k(g(h(8))) ) = -2*(16)+34
f(k(g(h(8))) ) = 2

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3 years ago