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Katarina [22]
3 years ago
9

The formula s= sqrt SA/6

Mathematics
1 answer:
ikadub [295]3 years ago
3 0
For this case we have the following equation:
 s = root (S.A / 6)
 Substituting values we have:
 For S.A = 180:
 s = root (180/6)
 s = root (30)
 For S.A = 120:
 s = root (120/6)
 s = root (20)
 s = root (4 * 5)
 s = 2 * root (5)
 Subtracting both values we have:
 root (30) - 2 * root (5)
 Answer:
 
root (30) - 2 * root (5)
 
option 2
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Abel Alonzo, Director of Human Resources, is exploring employee absenteeism at the Plano Power Plant. Ten percent of all plant e
Alex17521 [72]

Answer: 0.23

Step-by-step explanation:

Given : F is the event "works in the finishing department;"

and A is the event "is absent excessively."

Given : 10% of all plant employees work in the finishing department; 20% of all plant employees are absent excessively; and 7% of all plant employees work in the finishing department and are absent excessively.

i.e. P(A)= 0.20 ;  P(F)=0.10 ; P(A ∩ F) = 0.07

We know that P(X\cup Y)=P(X)+P(Y)-P(X\cap Y)

Then,

P(A\cup F)=P(A)+P(F)-P(A\cap F)\\\\\Rightarrow\ P(A\cup F)=0.20+0.10-0.07=0.23

Hence, the required answer is P(A\cup F)=0.23

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3 years ago
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Zepler [3.9K]

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5 0
2 years ago
A movie theater has 15 rows of State each rows have 24
mezya [45]
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3 0
3 years ago
Explain and correct the error made by a student who simplified this expression.
blagie [28]

Answer:

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Step-by-step explanation:

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4 0
3 years ago
X^2+43xy+590y^2 resolve into factors​
Natalija [7]

Step-by-step explanation:

We have:

x - y = 43 , xy = 15

To find, the value of x^2+y^2x

2

+y

2

= ?

∴ x - y = 43

Squaring both sides, we get

(x - y)^2(x−y)

2

= 43^243

2

⇒ x^2+y^2x

2

+y

2

- 2xy = 1849

Using the algebraic identity,

(a - b)^2(a−b)

2

= a^2+b^2a

2

+b

2

- 2ab

⇒ x^2+y^2x

2

+y

2

= 1849 + 2xy

Put xy = 15, we get

x^2+y^2x

2

+y

2

= 1849 + 2(15)

⇒ x^2+y^2x

2

+y

2

= 1849 + 30

⇒ x^2+y^2x

2

+y

2

= 1879

∴ x^2+y^2x

2

+y

2

= 1879

I will send hint follow this hint then slove it .

thankyou

7 0
3 years ago
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