From the top of a 100 ft air traffic control tower, an airplane is observed flying in at an angle of 32\displaystyle \degree°. I
1 answer:
Answer:
1974.6 feets
Step-by-step explanation:
The plane's altitude is : h + 100 feets
To obtain h, according to the attached picture ;
We can use trigonometry :
Tan θ = opposite / Adjacent
Opposite = h ; adjacent = 3000 feets
Tan 32° = h / 3000
h = 3000 * 0.6248693
h = 1874.6080
Plane's altitude :
h + 100 feets
(1874.6080 + 100) feets
= 1974.6 feets
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Answer:
In a rhombus, the diagonals bisect at right angles. That means half the diagonals form a right angle triangle then we can try the Pythagorean theorem. so -
one side of triangle = 6/2 =3 (half of the diagonal)
other side = 8/2 = 4
a^2 + b^2 = c2
3 ^2 + 4^2 = c^2
9+16 = c^2
c^2=25
c = = 5
the hypothenus forms one side of the rhombus and here the hypothenus is 5, so the lenght of a side is 5 !
