<em>My goodness, this is rather confusing in the way it is worded. Nevertheless, I will attempt to do what I can. Just please keep in mind that this is my own interpretation of the problem, and therefore could be... incorrect.</em>
<em>I think, to start out, we could set up the problem like so</em>
<em>15 + t ≥ 26</em>
<em>because t is not a set number. </em>
<em>Then all that is needed is to subtract 15 from both sides, and the equation becomes</em>
<em>t ≥ 11</em>
<em>So the resulting answer is t ≥ 11.</em>
<em />
<em>I hope that my interpretation helps.</em>
<em>-Toremi</em>
<em />
whether the answer choices
Answer C is the right answer.
Step-by-step explanation:
h(x) = f(x) * g(x)
h(x) = (2*3^x ) * ( 3*3^2x )
2 * 3 is easy, that will be 6.
The ground number 3 remains 3 in h(x), so that is easy too...
But with multiplying exponents, you can add them.
Let's concentrate only on the exponents of f(x) and g(x)... and add them...
x + 2x =3x
So, now combine the easy part with this new exponent, and you get <u>h(x)</u><u> </u><u>=</u><u> </u><u>6</u><u>*</u><u>(3)^(3x)</u>
<u>So</u><u> </u><u>answer C is the right answer.</u>
Answer:
(f+g)(x) = 60x + 400
Step-by-step explanation:
Given :
Amount in account A:
f(x) = 20x + 100
Amount in account B :
g(x) = 40x + 300
Total amount in Account A and B:
f(x) + g(x) = (20x + 100) + (40x + 300)
(f+g)(x) = (20x + 40x) + (100 + 300)
(f+g)(x) = 60x + 400
equation for first figure=2x+y=2
equation for second figure= 4x-y=8
(use formula x/a+y/b=1)
where, a=x component and b= y component..
