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Nataly [62]
3 years ago
6

What is the equation of the volume of a sphere

Mathematics
1 answer:
Evgesh-ka [11]3 years ago
8 0

Answer:

\frac{4}{3} *\pi  * r^{3}

r is radius of the sphere

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Simplify the radical expression.
levacccp [35]

Answer:

9√3

Step-by-step explanation:

√(81*3)

√81*√3

9√3

6 0
2 years ago
Which real-world story is represented by the addition problem (–2) + (–3) = –5?
tangare [24]

The answer is A.

If the submarine descended then it went below, and if it ascended it went above. Therefore:

"Descended 2 miles"= -2

"Then descended another 3 miles"= -3

(-2)+(-3)=-5

Adding two negatives together will give you a bigger negative so the submarine would then be 5 miles below its original location.

6 0
3 years ago
The slope of a line is the ratio of rise to run for any two points on a line. Is this a true statement? Explain in two to four s
Blizzard [7]

Answer:

True

Step-by-step explanation:

The slope is the ratio of rise to run for any two points on a line.

The rise is the change in vertical axis, y

Rise = y2 - y1

The run is the change in the horizontal axis, x

Run = x2 - x1

Slope is the ratio of both:

Rise / Run = (y2 - y1) / (x2 - x1)

8 0
2 years ago
Plugin y=-5 into either equation and solve for x<br> -6x-8y=-20 or x+y=5
nalin [4]

Answer:

x = 10

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
Suppose a certain computer virus can enter a system through an email or through a webpage. There is a 40% chance of receiving th
DedPeter [7]

Answer:

P = 0.42

Step-by-step explanation:

This probability problem can be solved by building a Venn like diagram for each probability.

I say that we have two sets:

-Set A, that is the probability of receiving this virus through the email.

-Set B, that is the probability of receiving it through the webpage.

The most important information in these kind of problems is the intersection. That is, that he virus enters the system simultaneously by both email and webpage with a probability of 0.17. It means that A \cap B = 0.17.

By email only

The problem states that there is a 40 chance of receiving it through the email. It means that we have the following equation:

A + (A \cap B) = 0.40

A + 0.17 = 0.40

A = 0.23

where A is the probability that the system receives the virus just through the email.

The problem states that there is a 40% chance of receiving it through the email. 23% just through email and 17% by both the email and the webpage.

By webpage only

There is a 35% chance of receiving it through the webpage. With this information, we have the following equation:

B + (A \cap B) = 0.35

B + 0.17 = 0.35

B = 0.18

where B is the probability that the system receives the virus just through the webpage.

The problem states that there is a 35% chance of receiving it through the webpage. 18% just through the webpage and 17% by both the email and the webpage.

What is the probability that the virus does not enter the system at all?

So, we have the following probabilities.

- The virus does not enter the system: P

- The virus enters the system just by email: 23% = 0.23

- The virus enters the system just by webpage: 18% = 0.18

- The virus enters the system both by email and by the webpage: 17% = 0.17.

The sum of the probabilities is 100% = 1. So:

P + 0.23 + 0.18 + 0.17 = 1

P = 1 - 0.58

P = 0.42

There is a probability of 42% that the virus does not enter the system at all.

5 0
3 years ago
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