The correct answers are:
Tissue level- similar cells work together to accomplish a goal.
Examples of tissue are muscles, skin, bone, and brain (nervous tissue).
A sponge is an example of an organism that is only organized to the cellular level.
Answer:
Your answer is B.
Explanation:
Since elements can't exactly "die", the element rather breaks down in the soil below it, and is used again upon the next plant or animal.
Hope I helped :)
Answer:
1. fragmentation- genetically identical
2. budding- genetically identical
3. haploid cells from two different mycelia fuse to form a zygote- genetically distinct
4. one hyphae creates spores through mitosis- genetically identical
Explanation:
1) Fragmentation is a form of asexual reproduction i.e. one parent, employed by certain organisms including fungi in which a FRAGMENT breaks off from the single parent to produce new cells. Since it is an asexual reproduction, the resulting cells will be GENETICALLY IDENTICAL.
2) Budding is another form of asexual reproduction that fungi undergoes e.g yeast. In the budding process, buds develop on the parent cell and later grow into mature cells that are GENETICALLY IDENTICAL to the parent cell.
3) In fungi, two different mycelia can produce haploid sex cells via the process of meiosis, which then fuse to produce a ZYGOTE. This method is a sexual means of reproduction. Hence, the zygote formed will be GENETICALLY DISTINCT from the parent.
4) Hyphae (threadlike filaments) of a fungi can via MITOTIC DIVISION produce spores, which then germinates under favorable conditions and grows into a new fungus. This new fungus cell is GENETICALLY IDENTICAL to the parent hyphae.
Answer:
3/4
Explanation:
If we assume simple dominance and independent assortment for each trait, we can use Mendel's Law of Segregation to predict the phenotypic proportions in the offspring of the parental cross AABBCc x AabbCc.
<h3><u>Gene A</u></h3>
AA x Aa
- F1 genotypes: 1/2 AA, 1/2 Aa
- F1 phenotypes: all A
<h3 /><h3><u>Gene B</u></h3>
BB x bb
- F1 genotypes: 1 Bb
- F1 phenotypes: all B
<h3 /><h3><u>Gene C</u></h3>
Cc x Cc
- F1 genotypes: 1/4 CC, 2/4 Cc, 1/4 cc
- F1 phenotypes: 3/4 C, 1/4 cc
We want to know the proportion of progeny with all dominant phenotype (A_B_C_). Since the genes are independent, we can multiply the probabilities of each gene to obtain the overall probability of having a ABC progeny:
<h3>1 A_ x 1 B_ x 3/4 C_ = 3/4 A_B_C_</h3>
