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andriy [413]
3 years ago
13

Given m||n find the value of x.

Mathematics
1 answer:
Marina CMI [18]3 years ago
5 0

Answer:

x =17

Step-by-step explanation:

The angles are supplementary so they add to 180

6x-20 + 6x - 4 = 180

12x -24 = 180

Add 24 to each side

12x-24+24 = 180+24

12x = 204

Divide by 12

12x/12 =204/12

x = 17

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solniwko [45]
You do what I’d 9-3 , 8-0 , then combined it and you will get the right answer
6 0
3 years ago
What is the inverse of the function below? f(x) = 5x - 2
kupik [55]

Answer:

B. f -1(x) = x + 2 / 5

f^{-1}(x)=\frac{x+2}{5}

Step-by-step explanation:

To find the inverse of a function we need to interchange x and y an solve for y.

Since f(x)=y, then

f(x)=5x-2

y=5x-2

x=5y-2

Add 2 to both sides

x+2=5y-2+2

x+2=5y

Divide both sides by 5

\frac{x+2}{5}=\frac{5y}{5}

\frac{x+2}{5}=y

y=\frac{x+2}{5}

f^{-1}(x)=\frac{x+2}{5}

We can conclude that the correct answer is B. f -1(x) = x + 2 / 5

6 0
3 years ago
The function f(x) is show on the graph. What is f(0)?
dexar [7]

Answer:

x = 0

Step-by-step explanation:

the origin

6 0
3 years ago
How do you find a unit vector that is orthogonal to both u = (1, 0, 1) v = (0, 1, 1)?
inna [77]

Answer:

one unit vector is ur=(-1/√3 ,1/√3 ,1/√3 )

Step-by-step explanation:

first we need to find a vector that is ortogonal to u and v . This vector r can be generated through the vectorial product of u and v , u X v :r=u X v =\left[\begin{array}{ccc}i&j&k\\1&0&1\\0&1&1\end{array}\right] = \left[\begin{array}{ccc}0&1\\1&1\end{array}\right]*i +  \left[\begin{array}{ccc}1&0\\1&1\end{array}\right]*j + \left[\begin{array}{ccc}1&0\\0&1\end{array}\right]*k = -1 * i + 1*j + 1*k = (-1,1,1)

then the unit vector ur can be found through r and its modulus |r| :

ur=r/|r| = 1/[√[(-1)²+(1)²+(1)²]] * (-1,1,1)/√3 =(-1/√3 ,1/√3 ,1/√3 )

ur=(-1/√3 ,1/√3 ,1/√3 )

7 0
4 years ago
You just got a free ticket for a boat ride, and you can bring along 4 friends! Unfortunately, you have 6 friends who want to com
Sliva [168]

Answer:

Step-by-step explanation:you can take 5

5 0
3 years ago
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