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AveGali [126]
4 years ago
14

Choose the number sentence that shows the distributive property of multiplication over addition.

Mathematics
1 answer:
Anarel [89]4 years ago
4 0

we know that

distributive property of multiplication over addition:

a \times (b+c)=a \times b + a \times c

now, we will verify each options

option-A:

3 × (4 + 5) = (3 × 4) + (3 × 5)

We can see that both sides match with property

so, this is TRUE

option-B:

3 × (4 + 5) = (3 + 4) × (3 + 5)

We can see that right side does not match with property

so, this is FALSE

option-C:

3 × (4 + 5) = (3 × 4) + 5

We can see that right side does not match with property

so, this is FALSE


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Igoryamba

Answer:

\frac{3t + 3}{5}  = 6 \\ 3 (\frac{t + 1}{5})  = 6 \\ \frac{t + 1}{5} = 2 \\ t + 1 = 10 \\ t = 9 \: or \\ 3t + 3 = 30 \\ 3t = 27 \\ t = 9

7 0
3 years ago
What is 0.91 in percentages?
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Answer: 91%

Step-by-step explanation:

6 0
3 years ago
I don’t understand, HELPPP
goldenfox [79]
\frac{-6xy^{3}z^5}{-36x^{2}y^{2}z^4}

First cross out the -6 and -36. Six will go into 6 one time and 6 will go into -36 six times so we have the following after crossing out.

\frac{-6xy^{3}z^5}{-36x^{2}y^{2}z^4}
\frac{xy^{3}z^5}{6x^{2}y^{2}z^4} <---After crossing out

Next cross out the x / x^2 which will give us the following:
\frac{xy^{3}z^5}{6x^{2}y^{2}z^4} 
\frac{y^{3}z^5}{6xy^{2}z^4} <---After crossing out

Now cross out the y^2 / y^3
\frac{y^{3}z^5}{6xy^{2}z^4}
\frac{yz^5}{6xz^4} <----After crossing out

All that is left is to cross out the z^5 / z^4 and we are done.
\frac{yz^5}{6xz^4}
\frac{yz}{6x} <----After crossing out and we are done.

\frac{-6xy^{3}z^5}{-36x^{2}y^{2}z^4} = \frac{yz}{6x}





8 0
3 years ago
Jamie used the distributive property to find the product of s(t) and h(t). His work was marked incorrect. Identify Jamie's mista
SSSSS [86.1K]

Complete Question:

Jamie used the distributive property to find the product of s(t) and h(t). His work was marked incorrect. Identify Jamie's mistake. What advice would you give Jamie to avoid this mistake in the future?

s(t)•h(t)= (3x-4)(2x-8)

= 6x² - 24x -8x - 32

= 6x² - 32x - 32

Answer:

Jamie made a mistake in his second line (6x² - 24x -8x - 32), by wrongly multiplying the operation signs. The last term should be +32, not -32.

Advice: Jamie should take note of the rule that applies when multiplying signs.

Step-by-step Explanation::

To find out where exactly Jamie made mistake, let's find the product of the given functions, step by step:

s(t)•h(t)= (3x-4)(2x-8)

Using distributive property, do the following:

3x(2x - 8) -4(2x - 8)

3x*2x -3x*8 -4*2x -4*-8

6x^2  - 24x - 8x + 32 (this is where Jamie made mistake. -4 * -8 = +32. NOT -32.)

Add like terms

6x^2  - 32x + 32

Jamie made a mistake in multiplying negative × negative. The last term in "6x² - 24x -8x - 32", should be +32. Negative × negative = +.

Therefore, it is advisable for Jamie to always take note of the rule that applies when multiplying signs.

8 0
3 years ago
Manchester Community College
frozen [14]

Answer:

1/3

Step-by-step explanation: im a young fellow im not sure

7 0
4 years ago
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