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kondor19780726 [428]
3 years ago
14

Find the slope of the lines shown in the graph

Mathematics
1 answer:
topjm [15]3 years ago
6 0
Hhuuhhhhuhhhhhhhhhgghgc
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An operator at the top of a lighthouse sights a sailboat. The point from which the sighting is made is 25 m above sea level. The
Aneli [31]

Answer:

141.78 m

Step-by-step explanation:

Let d = distance of boat from the base of the lighthouse

Tan 10 = 25/d

d tan 10 = 25

d = 25/tan 10

d = 141.78 m

4 0
2 years ago
Question 6 (Essay Worth 2 points)<br> Find all polar coordinates of point P = (2, 14°).
andrey2020 [161]

Answer:

(2,14°+360n) and (-2,14°+(2n+1)180°)

Step-by-step explanation:

You start out with (2, 14°)

The polar coordinate can be written as (r, 0) = (r, 0+2nπ) or

(r,0)=(-r,0+2(n=1)π), where n is any integer.

The polar coordinates point : p=(r,0) = (2,14°)

For the positive value of r,  the polar coordinate can be written as

p=(2,14°) = (2,14°+360n°), where n is any integer.

For the negative value of r ,  the polar coordinate can be written as

p=(2,14°) = (-2,14°+(2n+1)180°), where n is any integer.

All the polar coordinates of point P are(2,14°+360n) and (-2,14°+(2n+1)180°).

4 0
3 years ago
A bank is offering 3.5% simple interest on a savings account. If you deposit $7,500,how much interest will you earn in two years
arsen [322]

Answer:

525$

Step-by-step explanation:

8 0
3 years ago
Jason and Britton are driving to St. George. Jason got a 20 mile head start and drove an
harina [27]

Answer:

  2 hours, 150 miles

Step-by-step explanation:

The relation between time, speed, and distance can be used to solve this problem. It can work well to consider just the distance between the drivers, and the speed at which that is changing.

<h3>Separation distance</h3>

Jason got a head start of 20 miles, so that is the initial separation between the two drivers.

<h3>Closure speed</h3>

Jason is driving 10 mph faster than Britton, so is closing the initial separation gap at that rate.

<h3>Closure time</h3>

The relevant relation is ...

  time = distance/speed

Then the time it takes to reduce the separation distance to zero is ...

  closure time = separation distance / closure speed = 20 mi / (10 mi/h)

  closure time = 2 h

Britton will catch up to Jason after 2 hours. In that time, Britton will have driven (2 h)(75 mi/h) = 150 miles.

__

<em>Additional comment</em>

The attached graph shows the distance driven as a function of time from when Britton started. The distances will be equal after 2 hours, meaning the drivers are in the same place, 150 miles from their starting spot.

3 0
1 year ago
Jack was planting a tree. He was to dig a hole that was 3 feet deep for every 5 feet of tree height. How deep should he dig the
sweet-ann [11.9K]
I believe it is 10 feet deep.
7 0
3 years ago
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