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kondor19780726 [428]

3 years ago

14

Find the slope of the lines shown in the graph

1 answer:

topjm [15]3 years ago

6 0

Hhuuhhhhuhhhhhhhhhgghgc

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The area of a triangular block is 64 square inches. If the base of the triangle is twice the height, how long are the base and h

kkurt [141]

Answer:

Area of the triangle(A) is given by:

$A = \frac{1}{2}bh$ ....[1]

where,

b is the base and h is the height of the triangle.

As per the statement:

The area of a triangular block is 64 square inches.

⇒ $A= 64 in^2$

It is given that: If the base of the triangle is twice the height

⇒ $b = 2h$ .....[2]

Substitute these in [1] we have;

$64 = \frac{1}{2} \cdot (2h) \cdot h$

⇒ $64 = h^2$

or

$h^2 = 64$

⇒ $h = \sqrt{64} = 8$ inches.

Substitute h =8 in [2] we have;

$b = 2(8) = 16$ in.

therefore, the base and height of the triangle are: 16 inches and 8 inches.

4 0

3 years ago

Read 2 more answers

Which of the following is the graph of y = –2(2)x + 2?

Dafna11 [192]

Answer: Second graph is the correct option.

Step-by-step explanation:

Since we have given that

$y=-2(2)x+2\\\\y=-4x+2$

We will find the coordinate on y - axis first,

for coordinates on y-axis then x must be equal to 0.

so, put x=0,

$y=-4(0)+2\\\\y=0+2\\\\y=2$

So, according to this, Second graph has satisfied it.

Hence, Second graph is the correct option.

6 0

3 years ago

the weight of the bucket of fish was more than 23 pounds.Doria wants to write an inequality for the weight of the bucket of the

Sedbober [7]

Answer Choices

A. w > -23

B. w > 23 - CORRECT ANSWER

C. w < 23

D. w < -23

Answer: B. w > 23

3 0

3 years ago

I need the answer asap

Effectus [21]

Try b djdjwkkwkwkwkwwkwk ( I needed 20 characters)

8 0

3 years ago

Graph the functions on the same coordinate axis. {f(x)=−2x+1g(x)=x2−2x−3

NikAS [45]

Answer:

(2,-3) and (-2,5)

Step-by-step explanation:

Let us graph the two equations one by one.

1. $f(x)=-2x+1$

If we compare this equation with the slope intercept form of a line which is given as

$y=mx+c$

we see that m = -1 and c =1

Hence the slope of the line is -2 and the y intercept is 1. Hence one point through which it is passing is (0,1) .

Let us find another point by putting x = 1 and solving it for y

$y=-2(1)+1$

$y=-2+1 = -1$

Let us find another point by putting x = 2 and solving it for y

$y=-2(2)+1$

$y=-4+1 = -3$

Hence the another point will be (2,-3)

Let us find another point by putting x = -2 and solving it for y

$y=-2(-2)+1$

$y=+1 = 5$

Hence the another point will be (-2,5)

Now we have two points (0,1) ,(1,-1) , (2,-3) and (-2,5) we joint them on line to obtain our line

2.

$g(x)=y=x^2-2x-3$

$y=x^2-2x+1-1-3$

$y=(x-1)^2-4$

$(y+4)=(x-1)^2$

It represents the parabola opening upward with vertices (1,-4)

Let us mark few coordinates so that we may graph the parabola.

i) x=0 ; $y=y=(0)^2-2(0)-3=0-0-3=-3$ ; (0,-3)

ii)x=-1 ; $y=(-1)^2-2(-1)-3=1+2-3=0$ ; (-1,0)

iii) x=2 ; $y=(2)^2-2(2)-3 = 4-4-3 =-3$ ;(2,-3)

iii) x=1 ; $y=(1)^2-2(1)-3 = 1-2-3 =-4$ ;(1,-4)

iii) x=-2 ; $y=(-2)^2-2(-2)-3 = 4+4-3 =5$ ;(-2,5)

Now we plot them on coordinate axis and line them to form our parabola

When we plot them we see that we have two coordinates (2,-3) and (-2,5) are common , on which our graphs are intersecting. These coordinates are solution to the two graphs.

3 0

3 years ago