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3 years ago

15

Figure shows four paths along which objects move from a starting point to a final point, all im the same time interval. The path

s pass over a grid of equally spaced straight lines. Rank the paths according to the average velocity of the objects.

1 answer:

abruzzese [7]3 years ago

3 0

Answer:

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What is period and frequency

Nataliya [291]

Frequency is the number of occurrences of a repeating event per unit of time.It is also referred to as temporal frequency, which emphasizes the contrast to spatial frequency and angular frequency.

The period is the duration of time of one cycle in a repeating event, so the period is the reciprocal of the frequency.

3 0

4 years ago

a shopping bag can provide an upward force of 65N before breaking. A shopper puts 5 kg of groceries in the bag. If the shopper t

kipiarov [429]

Answer:

Since Force is Mass * Acceleration, the equation would be:

5kg * 2m^2 = 10N

<em>(10N is less than 65N)</em>

Therefore, it would not be enough force for the bag to break.

6 0

4 years ago

The charge density of radius 12.0 cm isgiven by with a = 1.40 μC/m 3 and r ismeasured radially outward from theorigin. What is t

Zigmanuir [339]

Answer:

The electric potential of the uniformly charge disk is 1392.1 V

Explanation:

Electric potential, for a uniformly charged disk at a distance A, is given as;

$V = \frac{\sigma}{2 \epsilon} [\sqrt{A^2 +R^2} -A]$

Where;

σ is the charge density = 1.40 μC/m³

ε is the permittivity of free space = 8.85 x 10⁻¹²

A is the distance above the disk = 40 cm = 0.4 m

R is the radius of the disk = 0.12 m

Substitute in these values into the equation above, we will have

$V = \frac{1.4 X 10^{-6}}{2X8,85X10^{-12}}[\sqrt{0.4^2 +0.12^2}-0.4] \\\\V = (79096.05)(0.0176) = 1392.1 V$

Therefore, the electric potential of the uniformly charge disk is 1392.1 V

3 0

3 years ago

A 80.0-kg airplane pilot pulls out of a dive by following, at a constant speed of 180km/hr, the arc of a circle whose radius is

wolverine [178]

Answer: 8.33m/s²

Explanation:

Mass of the airplane pilot = 80kg

The speed of plane v = 180km/h = 50m/s

The radius of circle r = 300 m

The acceleration of the plane will be calculated as:

a = v²/r

a = 50²/300

a = 2500/300

a = 8.33m/s²

Note that 180km/h was converted to m/s by

= (180 × 1000)/(60 × 60)

= 180000/3600

= 50m/s

1000 meters = 1 kilometer

60 minutes = 1 hour

60 seconds = 1 minute

3600 seconds = 1 hour

6 0

3 years ago

A golfer tees off from the top of a rise, giving the golf ball an initial velocity of 44 m/s at an angle of 25° above the horizo

mars1129 [50]

Answer:

a) $y=17.6m$

b) $v_{x}=39.87m/s\\v_{y}=-28.05m/s$

Explanation:

From the exercise we got our <u>initial data</u>

$v_{o}=44m/s\\\beta =25\\x=190m$

a) To find <u><em>maximum height</em></u> we know that at that point $v_{y}=0$

$v_{y} ^{2} =v_{oy} ^{2} +2a(y-y_{o} )$

$0=(44sin25)^{2} -2(9.8)y$

Solving for y

$y=\frac{(44sin25)^{2} }{2(9.8)} =17.6 m/s$

b) Since we know that the ball strikes the fairway 190 m away

$x=v_{ox}t\\ 190=44cos25t$

Solving for t

$t=4.76s$

Now, we can calculate the speed of the ball in both axes

$v_{x}=44cos25=39.87m/s$

$v_{y}=v_{oy}+at$

$v_{y}=44sin25-(9.8)(4.76)=-28.05m/s$

The <em>negative</em> sign means the direction of the ball at that point.

5 0

4 years ago