Answer:
V=1.19m/s
Explanation:
A 30-06 caliber hunting rifle fires a bullet of mass 0.018 kg with a velocity of 417 m/s to the right. The rifle has a mass of 6.29 kg. What is the recoil speed of the rifle as the bullet leaves the rifle?
this momentum.
it has to deal with the interaction between bullet and a gun
.lets have a deep dive into the solution
momentum is the product of mass of a body and the velocity
momentum of the bullet-=momentum of the gun
mv=MV
mass of bullet=0.018kg
v=velocity of bullet
M=mass of rifle 6.29kg
V=recoil velocity of the rifle gun
0.018*417=6.29*V
V=1.19m/s
mass is the quantity of matter in a body
velocity is change in displacement per time
It has acceleration while it's in your hand and you're in the process of flinging it, but we don't know how much.
It has acceleration ... pretty big ... during the short time between hitting the first blade of grass and coming to rest in the dirt, at the end of its trip.
From the time it leaves your hand until it hits the grass on the way down, its has the same constant, continuous acceleration ... 9.8 m/s^2 downward, the acceleration of gravity.
The greatest acceleration is probably at the end of the trip, after it hits the grass, and its speed drops to zero in a tiny fraction of a second.
