Answer:
Explanation:
Speed experimented by the ball before and after collision are determined by using Principle of Energy Conservation:
Before collision:
After collision:
The magnitude of the impulse delivered to the ball by the floor is calculated by the Impulse Theorem:
![Imp = (0.32\,kg)\cdot [(17.153\,\frac{m}{s} )-(-19.304\,\frac{m}{s} )]](https://tex.z-dn.net/?f=Imp%20%3D%20%280.32%5C%2Ckg%29%5Ccdot%20%5B%2817.153%5C%2C%5Cfrac%7Bm%7D%7Bs%7D%20%29-%28-19.304%5C%2C%5Cfrac%7Bm%7D%7Bs%7D%20%29%5D)
Answer:
(a) a = - 201.8 m/s²
(b) s = 197.77 m
Explanation:
(a)
The acceleration can be found by using 1st equation of motion:
Vf = Vi + at
a = (Vf - Vi)/t
where,
a = acceleration = ?
Vf = Final Velocity = 0 m/s (Since it is finally brought to rest)
Vi = Initial Velocity = (632 mi/h)(1609.34 m/ 1 mi)(1 h/ 3600 s) = 282.53 m/s
t = time = 1.4 s
Therefore,
a = (0 m/s - 282.53 m/s)/1.4 s
<u>a = - 201.8 m/s²</u>
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(b)
For the distance traveled, we can use 2nd equation of motion:
s = Vi t + (0.5)at²
where,
s = distance traveled = ?
Therefore,
s = (282.53 m/s)(1.4 s) + (0.5)(- 201.8 m/s²)(1.4 s)²
s = 395.54 m - 197.77 m
<u>s = 197.77 m</u>
Answer:
not sure just need points
Explanation:
a+b+c
The Earth takes very nearly (365 and 1/4) days to go around the sun.
If our calendar always had 365 days, then the year would end and re-start
too soon, and the beginning of Spring (and every other season) would
eventually drift into the months after March.
If our calendar always had 366 days, then the year would end and re-start
too late, and the beginning of Spring (and every other season) would
eventually drift into the months before March.
We can't make calendars with an extra quarter-day in each year. But we
keep them lined up with the real year by saving up the quarters, and adding
one full day to the calendar every 4 years.
(b)equation is not balanced
