(distance covered) divided by (time to cover the distance) is SPEED.
(straight-line distance and direction between start-point and end-point) is DISPLACEMENT.
(amount and direction of change in speed) divided by (time for the change) is ACCELERATION.
(amount and direction of change in momentum) divided by (time for the change) OR (mass) times (acceleration) is FORCE.
Answer:
<h3>The answer is 3.38 m/s²</h3>
Explanation:
The acceleration of an object given it's velocity and time taken can be found by using the formula

where
a is the acceleration
v is the velocity
t is the time
From the question
v = 27 m/s
t = 8 s
We have

We have the final answer as
<h3>3.38 m/s²</h3>
Hope this helps you
Fnet=m*a
a= Fnet/m
a=(20N[E]+9.0N[E])/ 12.0kg
a=2.4167m/s^2
a ≈ 2.4m/s^2
Answer:

Explanation:
First ship starts at Noon with speed 20 Knots towards West
now we know that 2nd ship starts at 6 PM with speed 15 Knots towards North West
so after time "t" of 2nd ship motion the two ships positions are given as


now we can find the distance between two ships as

now we have


now we will differentiate it with respect to time

here we know that

so we have

now we have


Answer:
135 m
Explanation:
Given:
vi = 12 m/s
vf = 18 m/s
t = 9s
Find: x
x = ½ (vf + vi) t
x = ½ (18 m/s + 12 m/s) (9 s)
x = 135 m