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blsea [12.9K]
3 years ago
13

A 80.0-kg airplane pilot pulls out of a dive by following, at a constant speed of 180km/hr, the arc of a circle whose radius is

300m. A) At the bottom of the circle, what are the direction and magnitude of his acceleration
Physics
1 answer:
wolverine [178]3 years ago
6 0

Answer: 8.33m/s²

Explanation:

Mass of the airplane pilot = 80kg

The speed of plane v = 180km/h = 50m/s

The radius of circle r = 300 m

The acceleration of the plane will be calculated as:

a = v²/r

a = 50²/300

a = 2500/300

a = 8.33m/s²

Note that 180km/h was converted to m/s by

= (180 × 1000)/(60 × 60)

= 180000/3600

= 50m/s

1000 meters = 1 kilometer

60 minutes = 1 hour

60 seconds = 1 minute

3600 seconds = 1 hour

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Convert 1 second in to solar day<br>​
jeka94

1 Days to Seconds = 86400 70 Days to Seconds = 6048000
2 Days to Seconds = 172800 80 Days to Seconds = 6912000
3 Days to Seconds = 259200 90 Days to Seconds = 7776000
4 Days to Seconds = 345600 100 Days to Seconds = 8640000
8 0
3 years ago
A 9500 kg boxcar traveling at 14 m/s strikes a stationary second car. The two stick together and move off with a speed of 6.0 m/
jasenka [17]

<u>Answer:</u> The mass of the second car is 12666.7 kg

<u>Explanation:</u>

To calculate the mass of car, we use the equation of law of conservation of momentum, which is:

m_1u_1+m_2u_2=(m_1+m_2)v

where,

m_1 = mass of car 1 = 9500 kg

u_1 = Initial velocity of car 1 = 14 m/s

m_2 = mass of car 2 = ? kg

u_2 = Initial velocity of car 2 = 0 m/s

v = Final velocity = 6.0 m/s

Putting values in above equation, we get:

(9500\times 14)+(m_2\times 0)=(9500+m_2)6.0\\\\m_2=\frac{9500\times 14}{6}-9500=12666.7kg

Hence, the mass of the second car is 12666.7 kg

6 0
4 years ago
Two blocks a and b ($m_a&gt;m_b$) are pushed for a certain distance along a frictionless surface. how does the magnitude of the
Yuki888 [10]

Answer:

the magnitude of the work done by the two blocks is the same.

Explanation:

The work done by block a on block b is given by:

W_a = F_a d

where Fa is the force exerted by block a on block b, and d is the distance they cover.

The work done by block b on block a is given by:

W_b = F_b d

where Fb is the force exerted by block b on block a, and d is still the distance they cover.

For Newton's third law, the force exerted by block a on block b is equal to the force exerted by block b on block a, therefore

F_a = F_b

and so

W_a=W_b

3 0
3 years ago
How does the momentum of a fast object compare to that of a slow object if they both have the same mass?
Varvara68 [4.7K]
The momentum of a fast object compared to that of a slow object even if they both have the same mass, is their velocities.

Having same mass but different velocities results in different momentum.

Example: mass = 10kg
Velocity 1 = 50 Velocity 2 = 100
Momentum 1 = 10×50 = 500 Ns
Momentum 2 = 10×100 = 1000 Ns

Hope it helped!
3 0
3 years ago
If we could see our own galaxy from 2 million light-years away, it would appear _________.
yaroslaw [1]

Answer:

It would appear as a flattened disk with a central bulge and spiral arms, spanning a few degrees across the sky.

Explanation:


I hope this helps! Have a great day!

Anygays-

5 0
2 years ago
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