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3 years ago

Write the phase as an algebraic expression. Nine less than a number n is written as

Mathematics

1 answer:

ivann1987 [24]3 years ago

8 0

Answer:

See Below

Step-by-step explanation:

n - 9

This is because, it is somewhat telling you to subtract 9 from a "n" number, such words as "less than" give signs to tell you to subtract!

Hope this Helps!

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Solve the math problem

Marianna [84]

Answer:

<1 = 109 (Vertically Opposite to <3)

<2 = 71 (Corresponding to <6)

<3 = 109

<4 = 71 (Alternate Interior to <6)

<5 = 109 (Alternate Interior to <3)

<6 = 71

<7 = 109 (Corresponding to <3)

<8 = 71 (Vertically Opposite to <6)

Step-by-step explanation:

<1 = 2x + 29

<2 = x + 31

<3 = 2x + 29

<4 = x + 31

<5 = 2x + 29

<6 = x + 31

<7 = 2x + 29

<8 = x + 31

<1 + <2 = 180

(2x + 29) + (x + 31) = 180

(2x +x) + (29 + 31) = 180

3x + 60 = 180

3x = 180 - 60 = 120

x = 120/3

x = 40

<1 = (2x + 29)

= (2 * 40) + 29

= 80 + 29

= 109

<2 = x + 31

= 40 +31

= 71

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3 years ago

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Xelga [282]

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Mars2501 [29]

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3 years ago

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Kayla drives 15 miles in 20 minutes. If she drove one hour in total at the same rate,

Rudik [331]

Answer:

45 miles

Step-by-step explanation:

first divide miles/minutes: 15 / 20 = 0.75

then multiply: 0.75 x 60 = 45

3 0

3 years ago

2067 Supp Q.No. 2a Find the sum of all the natural numbers between 1 and 100 which are divisible by 5. Ans: 1050

Alborosie

Answer:

1050

Step-by-step explanation:

Natural Numbers are positive whole numbers. They aren't negative, decimals, fractions. We can just divide 5 into 100 to find how many natural numbers go up to 100 and just add them but that is just to much.

There is a easier method.

E.g: Natural Numbers that are divisible by a Nth Number. is the same as adding the Nth Numbers to a multiple of that Nth Term. For example, let say we need to find numbers divisible by 2. We know that 4 is divisible by 2 because 4/2=2. We can add the Nth numbers which is 2 to 4. 4+2=6. And 6 is divisible by 2 because 6/2=3. We can call this a arithmetic series. A series which has a pattern of adding a common difference

Back to the problem, we can use the sum of arithmetic series formula,

$y = x( \frac{z {}^{1} + {z}^{n} }{2} )$

Where x is the number of terms in our sequence. Z1 is the fist term of our series. ZN is our last term. And y is the sum of all of the terms

The first term is 5, the numbers of terms being added is 20 because 100/5=20. The last term is 100.

$y = 20( \frac{5 + 100}{2} )$

$y = 20( \frac{105}{2} )$

$y = 1050$

5 0

3 years ago