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xxTIMURxx [149]
3 years ago
5

Which system of equations is inconsistent? Answer Choices Listed Below

Mathematics
1 answer:
Andrews [41]3 years ago
6 0

Answer:

B

Step-by-step explanation:

just took the test

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On a number line, will √20 be closer to 4.4 or 4.?
FinnZ [79.3K]
I’m pretty sure it’s closer to 4.4
3 0
3 years ago
Examine these points on line u and line v. Line u: (9, –8), (5, 4) Line v: (4, 2), (7, –7) How many points of intersection are t
Nezavi [6.7K]

There is no point of intersection between line u and line v.

Given that

These points on line u and line v.

Line u: (9, –8), (5, 4)

Line v: (4, 2), (7, –7)

We have to determine

How many points of intersection are there between line u and line v?

According to the question

To determine the point of intersection follows all the steps given below.

Line u: (9, –8), (5, 4)

The slope of the line u is,

\rm Slope = \dfrac{4-(-8)}{5-9}\\\\Slope = \dfrac{4+8}{-4}\\\\Slope = \dfrac{12}{-3}\\\\Slope = -4

And the value of c is at point (5, 4) is,

\rm y = mx+c\\\\4= -3\times 5+c\\\\c = 4+15\\\\c=19

The equation of u is y = -3x + 19.

And

Line v: (4, 2), (7, -7)

The slope of line V is,

\rm Slope = \dfrac{-7-(2)}{7-4}\\\\Slope = \dfrac{-7-2}{3}\\\\Slope = \dfrac{-9}{3}\\\\Slope = -3

And the value of c is at point (4, 2) is,

\rm y = mx+c\\\\2= -3\times 4+c\\\\c = 2+12\\\\c=14

The equation of u is y = -3x + 14.

The slopes of them are equal and their y-intercepted are not equal.

Line u is parallel to line v.

Hence, there is no point of intersection between line u and line v.

To know more about Slope click the link given below.

brainly.com/question/2514839

3 0
2 years ago
Will mark brainliest if your are correct!
zavuch27 [327]

Answer:

20.1

Step-by-step explanation:

4 0
4 years ago
Read 2 more answers
Hop skip and a leap, I need these answered so I can go to Vegas this week.
slavikrds [6]

Answer:

x=15/p                          p=-5 then x=(-3)

Step-by-step explanation:

4px+4=64

4px=60

px=15

7 0
4 years ago
What is the correct form of the partial fraction decomposition for 6x+7/(x+2)^2
andrezito [222]

If you mean

\dfrac{6x+7}{(x+2)^2}

the decomposition would be of the form

\dfrac{6x+7}{(x+2)^2} = \dfrac a{x+2} + \dfrac b{(x+2)^2}

We have

6x+7 = 6(x+2) - 5

which gives

\dfrac{6x+7}{(x+2)^2} = \dfrac{6(x+2)-5}{(x+2)^2} = \boxed{\dfrac6{x+2} - \dfrac5{(x+2)^2}}

Or, if you prefer the standard approach, combining the partial fractions on the right side of the equation above would have given

\dfrac{6x+7}{(x+2)^2} = \dfrac{a(x+2)+b}{(x+2)^2}

so that

6x+7 = a(x+2)+b = ax + 2a+b

Solve for <em>a</em> and <em>b</em> :

\begin{cases}a=6\\2a+b=7\end{cases} \implies a=6,b=-5

8 0
3 years ago
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