Answer:
It all depends.
Step-by-step explanation:
It depends on what you are trying to do, and what you want to solve for. If you are trying to distribute the 3 into 2, you would place the parentheses around the 2. I hope I was able to help, but there is not much that I can do without more clear instructions!
Answer:
There area 14 one cent stamps
Step-by-step explanation:
Let
x -----> the number of 1 cent stamps
y -----> the number of 8 cent stamps
z -----> the number of 12 cent stamps
we know that
0.01x+0.08y+0.12z=1.78 -------> equation A
x=y+4 ------> y=x-4 -----> equation B
x=2z -----> z=0.5x ------> equation C
substitute equation B and equation C in equation A and solve for x
0.01x+0.08(x-4)+0.12(0.5x)=1.78
0.01x+0.08x-0.32+0.06x=1.78
0.15x=1.78 +0.32
0.15x=2.10
x=14
therefore
There area 14 one cent stamps
Answer:
end of third year = 1,200*(1.02)^3 = 1,273.45 plus
end of second year = 1,200*(1.02)^2 = 1,248.48 plus
end of first year = 1,200*(1.02) = 1,224.00
Total = 3,745.9
Step-by-step explanation:
Answer:
D
Step-by-step explanation:
Cuz sqr root of 20 = 2 sqrt 5, -2 sqrt 5
Answer:
Option D, I agree with neither Elena nor Lin
Step-by-step explanation:
The remaining part of the question is attached herewith
Solution
As we can see in the image
ED is perpendicular to AB and BC is perpendicular to AB
Thus, as per the Pythagoras theorem,
AC^2 = AB^2 + BC^2
14^2 = 6^2 + BC^2
BC^2 = 196-36 = 160
BC = 12.649 OR 12.65
Hence, option D
I agree with neither Elena nor Lin