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Bess [88]
2 years ago
8

ppositional angle closure in eyes with narrow angles: comparison between the fellow eyes of acute angle-closure glaucoma and nor

motensive case
Mathematics
1 answer:
skad [1K]2 years ago
8 0

Here is the comparision

Purpose:To compare the topologic features of acute primary angle-closure glaucoma eyes before an attack to those of normotensive eyes, assuming that untreated fellow acute primary angle-closure glaucoma eyes are candidates for an acute attack.

Methods:Under dark-room conditions, ultrasound biomicroscopy was used to examine 50 eyes (12 fellow eyes of acute primary angle-closure glaucoma and 38 normotensive cases with a closure-possible narrow angle). Before any surgical or laser intervention, all eyes were examined and found to have normal pupillary response without the use of any topical drugs. Each eye was examined at four predetermined angle locations. The chamber angle configuration parameters were measured and compared between the two groups.

Result:Appositional angle closures were detected in 27 fellow eyes and 48 normotensive eyes with a closure-possible narrow angle. The incidence differed statistically between the two groups (69.2% in fellow eyes and 48% in normotensive eyes). In the fellow eye group, appositional angle closures beginning at the angle's entrance were more frequently detected. The distance between the iris root and the bottom of the angle varied significantly between groups.

Conclusion:Acute primary angle-closure glaucoma fellow eyes have different topologic features than normotensive narrow-angled eyes, as well as a higher incidence of appositional closure, which may predispose these eyes to an impending acute attack.

Learn more about glaucoma here:

brainly.com/question/1318395

#SPJ4

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Step-by-step explanation:

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An analyst for a large credit card company is going to conduct a survey of customers to examine their household characteristics.
zheka24 [161]

Answer:

We can conclude that the value of 1732 is a statistic who represent the sample selected. And the value of 1622 represent the population mean from all the customers with the previous data.

Step-by-step explanation:

Previous concepts

A statistic or sample statistic "is any quantity computed from values in a sample", for example the sample mean, sample proportion and standard deviation

A parameter is "any numerical quantity that characterizes a given population or some aspect of it".

Solution to the problem

For this case the analyst knows that from previous records that the mean for all the customers (that represent the population of interest) is \mu = 1622

He have a random sample of n =500 customers from the previous month and he knows that 1732 represent the sample mean for the selected customers calculated from the following formula:

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So on this case we can conclude that the value of 1732 is a statistic who represent the sample selected. And the value of 1622 represent the population mean from all the customers with the previous data.

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3 years ago
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Vitek1552 [10]

Answer:

y=-2\,(x-6)^2+246

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This agrees with the last option in the list of possible answers

Step-by-step explanation:

Recall that the maximum of a parabola resides at its vertex. So let's find the x and y position of that vertex, by using first the fact that the x value of the vertex of a parabola of general form:

y=ax^2+bx+c

is given by:

x_{vertex}=\frac{-b}{2\,a}

In our case, the quadratic expression that generates the parabola is:

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then the x-position of its vertex is:

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This is the price of the video game that produces the maximum profit (x = $6). Now let's find the y-position of the vertex using the actual equation for this value of x:

y=-2x^2+24x+174\\y_{vertex}=-2\,(6)^2+24\,(6)+174\\y_{vertex}=-72+144+174\\y_{vertex}=246

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Now, recall that we can write the equation of the parabola in what is called "vertex form" using the actual values of the vertex position (x_{vertex},y_{vertex}):

y-y_{vertex}=a\,(x-x_{vertex})^2\\y-246=-2\,(x-6)^2\\y=-2\,(x-6)^2+246

Therefore the answer is:

y=-2\,(x-6)^2+246

with the video game cost of x = $6

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Step-by-step explanation:

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