Answer:
Your answer would be 288
Step-by-step explanation:
You start off with the equation ( V= Bh )
Where "B" represents the area of the base ( which case you multiply 8 and 12 and thus getting 96 as your answer for finding "B")
and Lastly you multiply your "B" with the "h" ( which represents the height) and therefore you multiply 96 and 3
which equals to 288
( hope this helps )
x=2/9
Step-by-step explanation:
Step 1: Simplify both sides of the equation.
−4−3x=6x−6
−4+−3x=6x+−6
−3x−4=6x−6
Step 2: Subtract 6x from both sides.
−3x−4−6x=6x−6−6x
−9x−4=−6
Step 3: Add 4 to both sides.
−9x−4+4=−6+4
−9x=−2
Step 4: Divide both sides by -9.
−9x
−9
=
−2
−9
Answer:
![2xy\sqrt[3]{2x^2z}](https://tex.z-dn.net/?f=2xy%5Csqrt%5B3%5D%7B2x%5E2z%7D)
and 
.
Step-by-step explanation:
The given radical expression is
![\sqrt[3]{16x^5y^3z}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B16x%5E5y%5E3z%7D)
We have to simplify the above expression.
The above expression can be written as
![\sqrt[3]{(2\times 8)(x^{3+2})y^3z}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%282%5Ctimes%208%29%28x%5E%7B3%2B2%7D%29y%5E3z%7D)
![\sqrt[3]{(2\times 2^3)(x^3\times x^2)y^3z}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%282%5Ctimes%202%5E3%29%28x%5E3%5Ctimes%20x%5E2%29y%5E3z%7D)
![[\because a^{m+n}=a^ma^n]](https://tex.z-dn.net/?f=%5B%5Cbecause%20a%5E%7Bm%2Bn%7D%3Da%5Ema%5En%5D)
![\sqrt[3]{(2^3x^3y^3)(2x^2z)}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%282%5E3x%5E3y%5E3%29%282x%5E2z%29%7D)
![\sqrt[3]{(2xy)^3}\sqrt[3]{2x^2z}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%282xy%29%5E3%7D%5Csqrt%5B3%5D%7B2x%5E2z%7D)
![[\because (ab)^m=a^mb^m]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%28ab%29%5Em%3Da%5Emb%5Em%5D)
![[\because \sqrt[n]{x^n}=x]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Csqrt%5Bn%5D%7Bx%5En%7D%3Dx%5D)
It can be written as exponent form.
![[\because \sqrt[n]{a}=a^{\frac{1}{n}}]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%5Csqrt%5Bn%5D%7Ba%7D%3Da%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D%5D)
Therefore, the required expressions are and .
