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nordsb [41]
3 years ago
14

A cylinder is eight inches high with a radius of three inches. It contains a ball with a diameter of five inches. Approximately

what volume is left unoccupied in the cylinder? (Use 3.14 for pi)
Mathematics
1 answer:
Amiraneli [1.4K]3 years ago
6 0

Answer:

https://www.sunnyvaleisd.com/cms/lib3/TX01001155/Centricity/Domain/503/Unit%209%20Review%20Answers.pdf

Step-by-step explanation:

THIS IS NOT A SCAM!!!

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Hello, i’m stuck on this question can anyone help me please here is a pic, i’m putting 17 points that’s the highest it lets me..
kykrilka [37]

Answer:

So we can try all answers with -10 we get -11/4 = -2.75. And that is less so it works. -7 wont work because -8/4 = -2 and its not less than its the same. So the higher you go it wont work. So that rules out -7, -5, and -1. For 0 you get -1/4 = 0.25 which also doesn't work.

<h2><u>Only 1 answer: A</u></h2>
8 0
4 years ago
2. A square window has an area of 788 in2.
Xelga [282]
PART A:
1) plug in values given to you in the area formula: A=b^2--> 788=s^2
2) solve for x: x=28.071

PART B:
1) find he perimeter formula of a square: P=4s s being a side
2) plug in the value you got for part a as s: P=4(28.071) therefore, P=112.285
4 0
4 years ago
Need help ASAP fine the value of x. Round to the nearest tenth x=
White raven [17]

Answer:

x = 13.5

Step-by-step explanation:

To find x, we use the sine rule

For the sine rule,

the ratio of the sides to the sine of the angle facing the side is equal for all the sides of the triangle

Thus,

x/sin 34 = 11/ sin 27

x = 11 sin 34/sin 27

x = 13.5

5 0
3 years ago
10/9closest to 0,1/2or1
salantis [7]
10/9 can be simplified to 1 1/9, so it would be closer to 1
8 0
4 years ago
Read 2 more answers
Find the exact values of a) sec of theta b)tan of theta if cos of theta= -4/5 and sin&lt;0
Gre4nikov [31]

Answer:

Using trigonometric ratio:

\sec \theta = \frac{1}{\cos \theta}

\tan \theta = \frac{\sin \theta}{\cos \theta}

From the given statement:

\cos \theta = -\frac{4}{5} and sin < 0

⇒\theta lies in the 3rd quadrant.

then;

\sec \theta = \frac{1}{-\frac{4}{5}} = -\frac{5}{4}

Using trigonometry identities:

\sin \theta = \pm \sqrt{1-\cos^2 \theta}

Substitute the given values we have;

\sin \theta = \pm\sqrt{1-(\frac{-4}{5})^2 } =\pm\sqrt{1-\frac{16}{25}} =\pm\sqrt{\frac{25-16}{25}} =\pm \sqrt{\frac{9}{25} } = \pm\frac{3}{5}

Since, sin < 0

⇒\sin \theta = -\frac{3}{5}

now, find \tan \theta:

\tan \theta = \frac{\sin \theta}{\cos \theta}

Substitute the given values we have;

\tan \theta = \frac{-\frac{3}{5} }{-\frac{4}{5} } = \frac{3}{5}\times \frac{5}{4} = \frac{3}{4}

Therefore, the exact value of:

(a)

\sec \theta =-\frac{5}{4}

(b)

\tan \theta= \frac{3}{4}

7 0
4 years ago
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