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Alborosie
3 years ago
11

What reaction type is 4+22⟶4+22

Chemistry
1 answer:
aivan3 [116]3 years ago
6 0

Answer: CF_{4} + 2Br_{2} \rightarrow CBr_{4} + 2F_{2} is a single replacement reaction.

Explanation:

A chemical reaction in which one element of a compound is replaced by another element is called single replacement reaction.

For example, CF_{4} + 2Br_{2} \rightarrow CBr_{4} + 2F_{2}

Here, fluorine element in the compound CF_{4} is replaced by the element bromine.

Therefore, it is a single replacement reaction.

Thus, we can conclude that CF_{4} + 2Br_{2} \rightarrow CBr_{4} + 2F_{2} is a single replacement reaction.

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What is the correct equilibrium constant expression for equation P2(g)
sertanlavr [38]

Answer:

k = [F2]² [PO]² / [P2] [F2O]²

Explanation:

In a chemical equilibrium, the equilibrium constant expression is written as the ratio between the molar concentration of the products over the molar concentration of the reactants. Each species powered to its reaction coefficient. For the equilibrium:

P2(g) + 2F2O(g) ⇄ 2PO(g) + 2F2(g)

The equilibrium constant, k, is:

k = [F2]² [PO]² / [P2] [F2O]²

6 0
3 years ago
PLEASE EXPLAIN CORRECTLY! THX=)
tankabanditka [31]
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8 0
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What is an example of a risk management strategy
Nat2105 [25]

Answer:

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8 0
3 years ago
What is the normal pH range of a Base?
Karolina [17]

Answer:

7.35 - 7.45

Explanation:

The pH scale ranges from 0 (strongly acidic) to 14 (strongly basic or alkaline). A pH of 7.0, in the middle of this scale, is neutral. Blood is normally slightly basic, with a normal pH range of about 7.35 to 7.45. Usually, the body maintains the pH of blood close to 7.40.

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6 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP!
choli [55]

Answer:

\large \boxed{\text{D. 710 g}}

Explanation:

1. Calculate the molar mass of Na₂SO₄

\begin{array}{ccc}\textbf{Atoms} &\textbf{M}_{\textbf{r}} & \textbf{Mass/u}\\\text{2Na} & 23 & 46\\\text{1S} & 32 & 32\\\text{4O}&16 & 64\\&\text{TOTAL =} & \mathbf{142}\\\end{array}

The molar mass of Na₂SO₄ is 142 g/mol.

2. Calculate the moles of Na₂SO₄

\text{Moles of Na$_{2}$SO}_{4} = \text{2.5 L solution} \times \dfrac{\text{2.0 mol Na$_{2}$SO}_{4}}{\text{1 L solution}} = \text{5.0 mol Na$_{2}$SO}_{4}

3. Calculate the mass of Na₂SO₄

\text{Mass of Na$_{2}$SO}_{4} = \text{5.0 mol Na$_{2}$SO}_{4} \times \dfrac{\text{142 g Na$_{2}$SO}_{4}}{\text{1 mol Na$_{2}$SO}_{4}} = \text{710 g Na$_{2}$SO}_{4}\\\\\text{You need } \large \boxed{\textbf{710 g}} \text{ of Na$_{2}$SO}_{4}

6 0
3 years ago
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