The percent error associated with Jason’s measurement is 0.596%.
HOW TO CALCULATE PERCENTAGE ERROR:
- The percentage error of a measurement can be calculated by following the following process:
- Find the difference between the true value and the measured value of a quantity.
- Then, divide by the true value and then multiplied by 100
- The true value of the density of iron is 7.874 g/mL
- Jason observed value is 7.921 g/mL
Difference = 7.921 g/mL - 7.874 g/mL
Difference = 0.047 g/mL
Percentage error = 0.047/7.874 × 100
Percentage error = 0.596%.
Therefore, the percent error associated with Jason’s measurement is 0.596%.
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An old penny rusting, remember you can’t undo a chemical change
Answer:
The essence including its given problem is outlined in the following segment on the context..
Explanation:
The given values are:
Moles of CO₂,
x = 0.01962
Moles of water,



Compound's mass,
= 0.4647 g
Let the compound's formula will be:

Combustion's general equation will be:
⇒ 
On putting the estimated values, we get
⇒ 
⇒ 
⇒ 
⇒ 
Now,
x : y : z = 
= 
= 
= 
So that the empirical formula seems to be "C₃H₆O₂".
Answer:
0.08 mol L-1
Explanation:
Sulfuric acid Formula: H2SO4
Ammonia Formula: NH3
Ammonium sulfate Formula: (NH₄)₂SO₄
H2SO4 + 2NH3 = 2NH4+ + SO4 2-
H2SO4 + 2NH3 = (NH₄)₂SO₄
H2SO4 = (1/2)x (32.8 x 10^-3 L x 0.116 mol L-1)/25 x 10^-3 L
= 0.08 mol L-1
Answer:- 3.12 g carbon tetrachloride are needed.
Solution:- The balanced equation is:

From given actual yield and percent yield we will calculate the theoretical yield that would be further used to calculate the grams of carbon tetrachloride.
percent yield formula is:
percent yield = 


theoretical = 3.44 g
From balanced equation, there is 2:1 mol ratio between dichloethane and carbon tetrachloride.
Molar mass of dichloroethane is 84.93 gram per mol and molar mass of carbon tetrachloride is 153.82 gram per mol.

= 
So, 3.12 grams of carbon tetrachloride are needed to be reacted.