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Marta_Voda [28]
3 years ago
8

Complete the following road map for converting volume of A to volume of B for a titration of aqueous solution A with aqueous sol

ution B.
a. multiply by the molarity of B
b. multiply by the moles of B per moles of A
c. divide by the molarity of B
d. multiply by the molarity of A
e. divide by the molarity of A
f. multiply by the moles of A per moles of B

1. volume A (L)
2. moles A
3. moles B
4. volume B (L)
Chemistry
1 answer:
rodikova [14]3 years ago
4 0

Answer:

Explanation:

The solution of known concentration is expressed as molarity. Molarity is the mole fraction of solute (i.e. the dissolved substance) per liter of the solution, Molarity is also commonly called molar concentration.

Mathematically;

\mathtt{Molarity = \dfrac{moles \ of \ solute}{ liters \ of \ solution}}

To copy and complete the road map from the given question, we have the following array:

      Volume A (L)

               ↓

d. multiplied by the molarity of A

               ↓

          moles A

               ↓

b. multiplied by the moles of B / moles of A

               ↓

         moles B

               ↓

c. divided by the molarity of B

               ↓

        volume B (L)

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The actual density of iron is 7.874 g/mL. In a laboratory investigation, Jason finds the density of a piece of iron to be 7.921
mixas84 [53]

The percent error associated with Jason’s measurement is 0.596%.

HOW TO CALCULATE PERCENTAGE ERROR:

  • The percentage error of a measurement can be calculated by following the following process:
  1. Find the difference between the true value and the measured value of a quantity.
  2. Then, divide by the true value and then multiplied by 100

  • The true value of the density of iron is 7.874 g/mL
  • Jason observed value is 7.921 g/mL

Difference = 7.921 g/mL - 7.874 g/mL

Difference = 0.047 g/mL

Percentage error = 0.047/7.874 × 100

Percentage error = 0.596%.

Therefore, the percent error associated with Jason’s measurement is 0.596%.

Learn more: brainly.com/question/18074661?referrer=searchResults

5 0
2 years ago
Which activity is an example of chemical change?
frutty [35]
An old penny rusting, remember you can’t undo a chemical change
3 0
3 years ago
A 0.4647-g sample of a compound known to contain only carbon, hydrogen, and oxygen was burned in oxygen to yield 0.01962 mol of
Scilla [17]

Answer:

The essence including its given problem is outlined in the following segment on the context..

Explanation:

The given values are:

Moles of CO₂,

x = 0.01962

Moles of water,

\frac{y}{2} =0.01961

y=2\times 0.01961

  =0.03922

Compound's mass,

= 0.4647 g

Let the compound's formula will be:

C_{x}H_{y}O_{z}

Combustion's general equation will be:

⇒  C_{x}H_{y}O_{z}+x+(\frac{y}{4}-\frac{z}{2}) O_{2}=xCO_{2}+\frac{y}{2H_{2}O}

On putting the estimated values, we get

⇒  12\times x=1\times y+16\times z=0.4647

⇒  12\times 0.01962+1\times 0.03922+16\times z=0.4647

⇒  0.27466+16z=0.4647

⇒                     z=0.01187

Now,

x : y : z = 0.01962:0.03922:0.01187

           = \frac{0.01962}{0.0118}:\frac{0.03922}{0.0188}:\frac{0.0188}{0.0188}

           = 1.6:3.3:1.0

           = 3:6:2

So that the empirical formula seems to be "C₃H₆O₂".

8 0
3 years ago
A 25.0 mL sample of sulfuric acid is completely neutralized by adding 32.8 mL of 0.116 mol/L ammonia solution. Ammonium sulfate
Paul [167]

Answer:

0.08 mol L-1

Explanation:

Sulfuric acid Formula: H2SO4

Ammonia Formula: NH3

Ammonium sulfate Formula: (NH₄)₂SO₄

H2SO4 + 2NH3 = 2NH4+ + SO4 2-

H2SO4 + 2NH3 = (NH₄)₂SO₄

H2SO4 = (1/2)x (32.8 x 10^-3 L x 0.116 mol L-1)/25 x 10^-3 L

= 0.08 mol L-1

7 0
3 years ago
It is desired to produce 2.25 grams of dichloromethane (CH2Cl2) by the following reaction. If the percent yield of dichlorometha
Allushta [10]

Answer:- 3.12 g carbon tetrachloride are needed.

Solution:- The balanced equation is:

CH_4+CCl_4\rightarrow 2CH_2Cl_2

From given actual yield and percent yield we will calculate the theoretical yield that would be further used to calculate the grams of carbon tetrachloride.

percent yield formula is:

percent yield = (\frac{actual}{theoretical})100

65.5=(\frac{2.25}{theoretical})100

theoretical=(\frac{2.25(100)}{65.5})

theoretical = 3.44 g

From balanced equation, there is 2:1 mol ratio between dichloethane and carbon tetrachloride.

Molar mass of dichloroethane is 84.93 gram per mol and molar mass of carbon tetrachloride is 153.82 gram per mol.

3.44gCH_2Cl_2(\frac{1molCH_2Cl_2}{84.93gCH_2Cl_2})(\frac{1molCCl_4}{2molCH_2Cl_2})(\frac{153.82gCCl_4}{1molCCl_4})

= 3.12gCCl_4

So, 3.12 grams of carbon tetrachloride are needed to be reacted.

8 0
3 years ago
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