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3 years ago

Use the figure to calculate the volume of a section of round sheet metal pipe. The volume of the section shown = ________ cu in

Mathematics

1 answer:

rusak2 [61]3 years ago

6 0

Answer: 653.12 cu in

Step-by-step explanation: had it on a test

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The temperature fell from 0Degrees Fahrenheit to 6 and three-fifthsDegrees Fahrenheit below 0Degrees Fahrenheit in 2 and one-fif

stepan [7]

Answer:

B) -3 (Sorry if its overwhelming)

Explanation:

First, we have the given information of the weather over a 2 and 1/5 span

And we are asked to find the change per hour

We can first start by finding the change for 2 and 1/5 hours:

- Subtract the first amount by the second amount.

= (-6 3/5) - 0

= (-6 3/5) + 0

= -6 3/5

Now that we have the change for 2 and 1/5 hours we must find the change per hour:

- Divide the given dividend by the given divisor

= -6 3/5 ÷ 2 1/5

= -3

Hence, the temperature change per hour over a 2 1/5 hour span is -3° per hour

7 0

3 years ago

Read 2 more answers

2 divion 18 I need helpppppppp

Gnoma [55]

1 divided by 18 is .111111111

3 0

3 years ago

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A ladder is leaning against a vertical wall which is 5m high. The top of the ladder slides all the way down the wall so that the

Lynna [10]

Answer:

Do using Pythagoras theorem... Also before doing a question of height and distance always try to make the figure

Step-by-step explanation:

Use the two triangles ABC and ABD to first get the base and find the height of the ladder

7 0

3 years ago

Match the areas of the following squares with their correct side lengths.

9966 [12]

x=2

z=45

d=6

hope this helps

6 0

3 years ago

Evaluate the integral e^xy w region d xy=1, xy=4, x/y=1, x/y=2

LUCKY_DIMON [66]

Make a change of coordinates:

$u(x,y)=xy$
$v(x,y)=\dfrac xy$

The Jacobian for this transformation is

$\mathbf J=\begin{bmatrix}\dfrac{\partial u}{\partial x}&\dfrac{\partial v}{\partial x}\\\\\dfrac{\partial u}{\partial y}&\dfrac{\partial v}{\partial y}\end{bmatrix}=\begin{bmatrix}y&x\\\\\dfrac1y&-\dfrac x{y^2}\end{bmatrix}$

and has a determinant of

$\det\mathbf J=-\dfrac{2x}y$

Note that we need to use the Jacobian in the other direction; that is, we've computed

$\mathbf J=\dfrac{\partial(u,v)}{\partial(x,y)}$

but we need the Jacobian determinant for the reverse transformation (from $(x,y)$ to $(u,v)$ . To do this, notice that

$\dfrac{\partial(x,y)}{\partial(u,v)}=\dfrac1{\dfrac{\partial(u,v)}{\partial(x,y)}}=\dfrac1{\mathbf J}$

we need to take the reciprocal of the Jacobian above.

The integral then changes to

$\displaystyle\iint_{\mathcal W_{(x,y)}}e^{xy}\,\mathrm dx\,\mathrm dy=\iint_{\mathcal W_{(u,v)}}\dfrac{e^u}{|\det\mathbf J|}\,\mathrm du\,\mathrm dv$
$=\displaystyle\frac12\int_{v=}^{v=}\int_{u=}^{u=}\frac{e^u}v\,\mathrm du\,\mathrm dv=\frac{(e^4-e)\ln2}2$

8 0

3 years ago