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3 years ago

I need to know what X=

Mathematics

1 answer:

laila [671]3 years ago

5 0

Answer:

Lol I learned about this today in class, but I couldnt pay attention cuz I started crying about something

Step-by-step explanation:

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Siri, who is not yet 22 years old, is five years older than Lily. Write and solve an

Zolol [24]

Answer:

22-5= L

L = 17

Step-by-step explanation:

8 0

2 years ago

Let P(x) denote the statement "2x+5 > 10." Which of the following is true?

ruslelena [56]

Answer: P(3) is True

Step-by-step explanation:

The given statement is an inequality denoted as P(x). To find out which of the options is true you have to evaluate each given value of X in the inequality and perform the arithmetic operations, then you have to see if the expression makes sense.

For P(0): Replace X=0 in 2x+5>10

2(0)+5>10

0+5>10

5>10 is false because 5 is not greater than 10

For P(3): Replace X=3 in 2x+5>10

2(3)+5>10

6+5>10

11>10 is true because 11 is greater than 10

For P(2): Replace X=2 in 2x+5>10

2(2)+5>10

4+5>10

9>10 is false

For P(1): Replace X=1 in 2x+5>10

2(1)+5>10

2+5>10

7>10 is false

4 0

2 years ago

What is the slope of the line that passes through the points A(0, 1) and B(2, 7)?

Alenkinab [10]

Answer:

Step-by-step explanation:

We can use the formula [ y2-y1/x2-x1 ] to solve.

7-1/2-0

6/2

Best of Luck!

4 0

3 years ago

Simplify the exponential expression. (−8) 2 =

sweet-ann [11.9K]

Answer:

-16

Step-by-step explanation:

6 0

3 years ago

Need step-by-step. Please answer correctly. This determines what grade I get. I will mark brainliest to the first person who ans

tatyana61 [14]

Answer:

3√3

Step-by-step explanation:

For the problem shown here, your answer 3√3 is correct.

When there is a radical by itself in the denominator, you multiply numerator and denominator by a radical that results in the product being rational. For a square root, that will usually be the same square root:

$\dfrac{9}{\sqrt{3}}=\dfrac{9}{\sqrt{3}}\cdot\dfrac{\sqrt{3}}{\sqrt{3}}=\dfrac{9\sqrt{3}}{3}=\boxed{3\sqrt{3}}$

If the problem has a sum in the denominator involving a square root, then you multiply numerator and denominator by the conjugate of that sum (the sum with the sign changed). This uses the special product "difference of squares" to eliminate the radical term.

<u>Example</u>:

$\dfrac{9}{2-\sqrt{3}}=\dfrac{9}{2-\sqrt{3}}\cdot\dfrac{2+\sqrt{3}}{2+\sqrt{3}}=\dfrac{9(2+\sqrt{3})}{2^2-(\sqrt{3})^2}=\dfrac{18+9\sqrt{3}}{4-3}\\\\=\boxed{18+9\sqrt{3}}$

It is easy to demonstrate that none of the offered choices for this problem has the same value as 9/√3.

9/√3 ≈ 5.196. Offered choices have values of about 4.798, 1.732, 6.681, 23.196 -- none even close.

Please discuss this question with your teacher.

3 0

2 years ago