Question

What is the maximum or minimum of the quadratic function y = 16x^2 +40x +25

Answer 1

Y = 16x^2+ 40x + 25 

The sign before the 16 is positive, so it's a parabola with a minimum. The x coordinate of the minimum is: 
x=-b/2a=-40/32=5/4=-1.25 

If you fill that in, you get y=0 

so the coordinates are (1.25, 0)