What is the maximum or minimum of the quadratic function y = 16x^2 +40x +25

1 answer:

6 0

Y = 16x^2+ 40x + 25

The sign before the 16 is positive, so it's a parabola with a minimum. The x coordinate of the minimum is: 
x=-b/2a=-40/32=5/4=-1.25 

If you fill that in, you get y=0 

so the coordinates are (1.25, 0)

You might be interested in

According to general equation for conditional probability, if P(A^B) = 2/3 and P(B) = 3/4, what is P(A|B)?

Alexxx [7]

Answer:

Step-by-step explanation:

5 0

3 years ago

Fill the missing values in the ratio table

kramer

Answer:

A really out of focus picture, but I think this might be what you want.

Step-by-step explanation:

8 0

3 years ago

What is the most precise name for quadrilateral ABCD with vertices A(–5,2), B(–3, 5),C(4, 5),and D(2, 2)?

bonufazy [111]

Answer: ABCD is a parallelogram.

Step-by-step explanation:

First we plot these point on a graph as given in attachment.

From the attachment we can observe that AD || BC || x-axis .

also, AB ||CD, that will make ABCD a parallelogram , but to confirm we check the property of parallelogram "diagonals bisect each other" , i.e . "Mid point of both diagonals are equal".

Mid point of AC= $(\dfrac{-5+4}{2},\dfrac{2+5}{2})=(\dfrac{-1}{2},\dfrac{7}{2})$