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Physics

1 answer:

Aleksandr [31]3 years ago

5 0

B and C because an earthquake does not directly affect gravity, and precipitation doesn’t fall, it is water surfacing

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The water is flowing through the horizontal constricted pipe. The pressure at one end is 4500Pa, speed is 3m/s and area of cross

Oksana_A [137]

The speed and pressure at another end will be 9 m/sec and -31500 pascals.

<h3>What is gauge pressure?</h3>

The difference between absolute pressure and atmospheric pressure is known as gauge pressure. Relative pressure is another name for gauge pressure.

Given data in problem is;

For horizontal pipe, Z₁=Z₂

Pressure at end 1, P₁ = 4500Pa

Speed at end 1, V₁ = 3 m/sec

Speed at end 2, V₂ = ? m/sec

Area of cross-section at end 1,A₁ =A

Area of cross-section at end 1,A₂ = A/3

From the continuity equation;

A₁V₁=A₂V₂

A× 3 = (A/3)×V₂

V₂ = 9 m/sec

From Bernoulli's equation;

$\rm \frac{P_1}{\rho g} + \frac{v_1^2}{2g} +Z_1 = \frac{P_2}{\rho g} + \frac{v_2^2}{2g} +Z_2 \\\\ \frac{P_1-P_2}{\rho g } = \frac{v_2^2-v_1^2}{2g} \\\\ \frac{P_1-P_2}{\rho} = \frac{v_2^2-v_1^2}{2} \\\\ \frac{4500-P_2}{1000} = \frac{9^2-3^2}{2} \\\\ 4500 -P_2 = 36000 \\\\ P_2 = - \ 31,500 \ pa$

Hence the speed and pressure at another end will be 9 m/sec and -31500 pascals.

To learn more about the gauge pressure, refer to the link;

brainly.com/question/14012416

#SPJ1

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2 years ago

If two objects with different masses are pushing each other, which exerts the greater force?

Sedaia [141]

Newton's 3rd law of motion says that for every action there is an equal and opposite reaction.

This means that the smaller mass exerts a force on the larger mass that is equal in magnitude and opposite in direction to the force that the larger mass exerts on the smaller mass.

Choice 2

6 0

3 years ago

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Early one February morning you go outside to build a snow man. You make a 3.2kg snowball and lift it to a height of 1.2m, then c

Verdich [7]

First the amount of work done in lifting up the snow ball to a height of 1.2m is equal to the potential energy of the ball after the lift.

Therefore mass× gravitational pull×height will give us the work done

=3.2kg ×9.8N/kg×1.2m

=37.632J

then, the work done over the 25m distance if found by the following formula: work done=force×distance

=1.0N×25m