You can find the emf of the battery by using:
Q = CV.
Q = Charge in capacitor plates = 30μC
C = Capacitance of the capacitor = 30μF
V = Q/C = 30/30 = 1V
Ans: The emf of the battery = 1V.
H = 40 m, the height from which the ball is dropped.
m = 1 kg, the mass of the ball
Assume g = 9.8 m/s² and neglect air resistance.
The initial vertical velocity is zero.
If t = the time of flight, then
40 m = (1/2)*g*(t s)² = 0.5*9.8*t²
t² = 40/4.9 = 8.1633
t = 2.857 s
Answer: 2.9 s (nearest tenth)
Answer:
For any v-t graph the acceleration is the slope of the graph. For average acceleration in a time period ‘t’ consider the change in velocity in time t and divide it by the time t. For instantaneous acceleration you need to go into the realm of differential calculus.
Explanation:
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