A = delta v over delta t delta v is calculated with final velocity less initial velocity so delta v is 14 - 6 that is 8m/s and delta t is calculated with final time less initial time as initial always is 0 then is 1 - 0 that is 1 then a = 8m/s over 1 that is 8 then the acceleration is 8m/s^2 (remember that is squared.)
Answer:
The flea will reach to a height of 5.2 cm.
Explanation:
Let us assume it is given that, a flea reaches a takeoff speed of 1.0 m/s over a distance of 0.50 mm.
Initial speed, u = 1 m/s
Initial distance, x = 0.5 mm
We need to find the height reached by the flea. Using third equation of motion to find it.
At maximum height, its final speed, v = 0
Here, a = -g
or
h = 5.2 cm
So, the flea will reach to a height of 5.2 cm.
Answer:
It Is violet
Explanation:
It has the shortest wavelengths and the shorter the wavelengths the higher the frequency.
Answer:
Q = 47.06 degrees
Explanation:
Given:
- The transmitted intensity I = 0.464 I_o
- Incident Intensity I = I_o
Find:
What angle should the principle axis make with respect to the incident polarization
Solution:
- The relation of transmitted Intensity I to to the incident intensity I_o on a plane paper with its principle axis is given by:
I = I_o * cos^2 (Q)
- Where Q is the angle between the Incident polarized Light and its angle with the principle axis. Hence, Using the relation given above:
Q = cos ^-1 (sqrt (I / I_o))
- Plug the values in:
Q = cos^-1 ( sqrt (0.464))
Q = cos^-1 (0.6811754546)
Q = 47.06 degrees
