Segment PT || segment QS, Given
segment PT ≅ segment QS,
∠T ≅ ∠S
Angle TPQ = Angle SQR PR is a transversal cutting parallel segments SQ and TP
So....it makes corresponding angles TPQ and SQR equal
ΔPQT ≅ ΔQRS ASA congruency
Answer:
Booster club purchased 5 pies.
Step-by-step explanation:
Let the number of pies purchased by booster club be represented by n. The school also donated 3 pies to sell.
So that,
Total number of pies = n + 3
Given that there was 64 pieces of pies to sell after cutting each pie into 8 pieces.
Thus,
8( n + 3) = 64
8n + 24 = 64
8n = 64 - 24
8n = 40
Divide both sides by 8 to have,
n = 5
The number of pies purchased by booster club is 5.
Answer:
523.6
Step-by-step explanation:
Here is the equation to get that answer:
V=4/3πr3=4/3·π·53≈523.59878
113.7 * 30 = ¥3,411
hope this helped
Answer:
p = 11.2
Step-by-step explanation:
The computation is shown below:
Data provided in the question
2.6(5.5p – 12.4) = 127.92
Now
Distributive Propertyis
14.3p - 32.24 = 127.92
Addition Property is
14.3p = 127.92 + 32.24
Division Property is
14.3p ÷ 14.3 = 160.16 ÷ 14.3
p = 11.2
We simply find the value of p by applying the distributive property, addition property, and the division property and the same is to be considered