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devlian [24]
3 years ago
5

Which equation would help solve for x?

Mathematics
1 answer:
timama [110]3 years ago
3 0

Answer:

4x + 107 = 180

Step-by-step explanation:

105 + 4x + 2 = 180

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pashok25 [27]

find the area the get the premiraterStep-by-step explanation:add

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3 years ago
Nick decided to take 2/5 of the money in his bank account and donate it to a local charity. If nick donated $70 to a local chari
S_A_V [24]

Answer:

<u> The total amount = $175</u>

Step-by-step explanation:

Let the total amount in his bank account = x

Nick decided to take 2/5 of the money in his bank account and donate it to a local charity

So, he donates with \frac{2}{5} x

If nick donated $70 to a local charity

so, \frac{2}{5} x = 70

solve for x

∴ x = 5*70/2 = 350/2 = $175

<u>So, The total amount = $175</u>

3 0
3 years ago
PLEASE HELP! BRAINLIEST! So desperate.
PSYCHO15rus [73]

Answer:

<B = 15

Step-by-step explanation:

A triangle adds up to 180 degrees.

Since these triangles are similar, the sides are located in the same spot. (A is in same spot as D, etc.)

A=75

F=90

75 + 90 + x = 180

165 + x = 180

x = 15

8 0
4 years ago
Rectangle ABCD has vertex coordinates A(1, -2), B(4, -2), C(4,-4), and D(1,
hram777 [196]
The coordinates of C is, (3,-1)
A is the. Answer
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3 years ago
Anyone knows how to do questions 7 and 8? 15 pts!!
Oksi-84 [34.3K]
7) Certainly there is a typo in the statement, just see that the expression of item (ii) is different from that of item (i). Probably the correct expression is: 2x^2-4x+5. With this consideration, we can continue.

(i) Let E the expression that we are analyzing:

E=2x^2-4x+5\\\\ E=2x^2-4x+2-2+5\\\\ E=2(x^2-2x+1)-2+5\\\\ E=2(x-1)^2+3

Since (x-1)² is a perfect square, it is a positive number. So, E is a result of a sum of two positive numbers, 2(x-1)² and 3. Hence, E is a positive number, too.

(ii) Manipulating the expression:

2x^2+5=4x\\\\ 2x^2-4x+5=0

So, it's the case when E=0. However, E is always a positive number. Then, there is no real number x that satisfies the expression.

8) Let E the expression that we want to calculate:

E=(2+1)(2^2+1)(2^4+1)\cdot ...\cdot(2^{32}+1)+1\\\\ E-1=(2+1)(2^2+1)(2^4+1)\cdot ...\cdot(2^{32}+1)

Multiplying by (2-1) in the both sides:

(2-1)(E-1)=(2-1)(2+1)(2^2+1)(2^4+1)\cdot ...\cdot(2^{32}+1)\\\\ (E-1)=\underbrace{(2-1)(2+1)}_{2^2-1}(2^2+1)(2^4+1)\cdot ...\cdot(2^{32}+1)\\\\ (E-1)=\underbrace{(2^2-1)(2^2+1)}_{2^4-1}(2^4+1)\cdot ...\cdot(2^{32}+1)\\\\ ... Repeating the process, we obtain: ...\\\\ E-1=(2^{32}-1)(2^{32}+1)\\\\ E-1=2^{64}-1\\\\ \boxed{E=2^{64}}
3 0
4 years ago
Read 2 more answers
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