Question

A field is to be fertilized at a cost of $0.07 per square yard. The rectangular part of the field is 125 yd long and the diameter of each semicircle is 40 yd. Find the cost of fertilizing the field.

Answer 1

Answer:

The cost of fertilizing the field is $\ 437.96$

Step-by-step explanation:

we know that

The area of the figure is equal to the area of the rectangle plus the area of a complete circle (two semicircles)

Step 1

Find the area of the rectangle

The area of rectangle is equal to

$A=LW$

where

L is the length side of rectangle

w is the width side of the rectangle

In this problem we have

$L=125\ yd$

$W=D=40\ yd$

substitute

$A=125*40=5,000\ yd^{2}$

Step 2

Find the area of the circle

The area of the circle is equal to

$A=\pi r^{2}$

where

r is the radius of the circle

In this problem we have

$r=40/2=20\ yd$

substitute

$A=\pi (20)^{2}=1,256.64\ yd^{2}$

Step 3

Find the area of the figure

Adds the area of rectangle and the area of the circle

$5,000\ yd^{2}+1,256.64\ yd^{2}=6,256.64\ yd^{2}$

Step 4

Find the cost

Multiply the total area by $0.07 \frac{\ }{yd^{2} }$

so

$6,256.64*0.07=\ 437.96$