Answer:
(a)
The function f is continuous at [1,e] and differentiable at (1,e), therefore
the mean value theorem applies to the function.
(b)
= 1.71828
Step-by-step explanation:
(a)
The function f is continuous at [1,e] and differentiable at (1,e), therefore
the mean value theorem applies to the function.
(b)
You are looking for a point
such that
![\frac{1}{c} = \frac{\ln(15e)-\ln(15*1)}{e-1} = \frac{\ln(15e/15)}{e-1} = \frac{\ln(e)}{e-1} = \frac{1}{e-1}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7Bc%7D%20%3D%20%5Cfrac%7B%5Cln%2815e%29-%5Cln%2815%2A1%29%7D%7Be-1%7D%20%3D%20%5Cfrac%7B%5Cln%2815e%2F15%29%7D%7Be-1%7D%20%3D%20%5Cfrac%7B%5Cln%28e%29%7D%7Be-1%7D%20%3D%20%5Cfrac%7B1%7D%7Be-1%7D)
You have to solve for
and get that
= 1.71828
Let's find the mean of all the values first.
6.3+6.4+6.5+6.6+6.8+6.8+7.5= 46.9
Let's divide by the number of values.
46.9÷7=
6.7
Now let's find the distance that each number is away from 6.7 and find the mean of those numbers.
0.4+0.3+0.2+0.1+0.1+0.1+0.8=
.2857
≈ 0.3
So, the absolute deviation is 0.3.
The perimeter of the a and BC is 14 unitsBecause if you add all of the sides together you get 14 and I need points
Answer: 9 and 7eights
Step-by-step explanation: Divide using long division. The whole number portion will be the number of times the denominator of the original fraction divides evenly into the numerator of the original fraction, and the fraction portion of the mixed number will be the remainder of the original fraction division over the denominator of the original fraction. Which would equal, 9 and 7eights.
Answer:
Raymond's mistake was on the last step, since he didn't square root both sides
The correct answer should be
![c = \sqrt{41}](https://tex.z-dn.net/?f=c%20%3D%20%5Csqrt%7B41%7D)
Step-by-step explanation:
![a^2 + b^2 = c^2\\4^2 + 5^2 = c^2\\16 + 25 = c^2\\c^2 = 41\\c = \sqrt{41}](https://tex.z-dn.net/?f=a%5E2%20%2B%20b%5E2%20%3D%20c%5E2%5C%5C4%5E2%20%2B%205%5E2%20%3D%20c%5E2%5C%5C16%20%2B%2025%20%3D%20c%5E2%5C%5Cc%5E2%20%3D%2041%5C%5Cc%20%3D%20%5Csqrt%7B41%7D)
Good luck!