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3 years ago

Plz help me well mark brainliest if correct.............

Mathematics

2 answers:

Marta_Voda [28]3 years ago

6 0

The answer is 11 :) hope that helped

MrRissso [65]3 years ago

4 0

Answer:

Yup, 11 is the answer. because 4 -15 is 11.

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1/2(8x-6) = x + 9 solve ... hurry

QveST [7]

Answer:

x=4

Step-by-step explanation:

4x-3=x+9

4x-x-3=9

4x-x=9+3

3x=9+3

3x=12

3/3

12/3=4

x=4

5 0

3 years ago

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Can u guys please help a poor soul <br> 1/root 5 - root 3

Stolb23 [73]

Answer:

1/√5+√3= 1/√5+√3×√5-√3/√5-√3 = √5-√3/(√5)^2-(√3)^2 {(a+b)(a-b)= (a)^2-(b)^2} =√5-√3/5-3 =√5-√3/2 ans... Do you satisfied to my given answer

Step-by-step explanation:

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2 years ago

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Please Help!!

Ede4ka [16]

Answer:

-3, -1, 1, 7

Step-by-step explanation:

took the test. Now i have to retake it ;(

7 0

3 years ago

Rectangle ABCD is similar to rectangle RSTU .

Alenkasestr [34]

Answer:

The scale factor of a dilation from ABCD to RSTU is $\frac{1}{2}$

Step-by-step explanation:

We know that the rectangle ABCD is similar to rectangle RSTU.

Given that in rectangle ABCD the longest sides are DC and AB and in the rectangle RSTU the longest sides are UT and RS ⇒ The scale factor of a dilation will transform the sides DC and AB into UT and RS

Working with the lengths of the sides :

DC.(Scale factor) = UT

AB.(Scale factor) = RS

Replacing with the values of the lengths (Scale factor : SF) :

$DC.SF=UT\\(90ft).(SF)=45ft\\SF=\frac{45ft}{90ft} \\SF=\frac{1}{2}$

$AB.SF=RS\\(90ft).(SF)=45ft\\SF=\frac{45ft}{90ft} \\SF=\frac{1}{2}$

Notice that the scale factor is dimensionless.

We can verify this result with the sides AD and BC :

$AD.SF=UR\\50ft.(\frac{1}{2})=25ft\\ 25ft=25ft$

$BC.SF=TS\\50ft.(\frac{1}{2})=25ft\\ 25ft=25ft$

The scale factor (SF) is $\frac{1}{2}$

7 0

3 years ago

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Combine the following fractions by addition or subtraction as directed.

Marina86 [1]

Answer: $\frac{6}{y^2-xy}-\frac{6}{x^2-xy}=\frac{6(x+y)}{xy(y-x)}$

Explanation:

Combining the fractions, we have:

$\begin{gathered} \frac{6(x^2-xy)-6(y^2-xy)}{(x^2-xy)(y^2-xy)} \\ \\ =\frac{6x^2-6xy-6y^2+6xy}{(x^2-xy)(y^2-xy)} \\ \\ =\frac{6x^2-6y^2}{x(x-y).y(y-x)} \\ \\ =\frac{6(x-y)(x+y)}{-xy(x-y)^2} \\ \\ =\frac{-6(x+y)}{xy(x-y)} \\ \\ =\frac{6(x+y)}{xy(y-x)} \end{gathered}$

8 0

1 year ago