Open circle going to the right?
First, you have to represent each given set by listing their elements. Observe:
• D = {x | x is a whole number}
D = <span>ℤ
</span>D = {..., – 3, – 2, – 1, 0, 1, 2, 3, ...}
• E = {x | x is a perfect square between 1 and 9}
("between" does not include the boundaries)
E = {x | x is a perfect square, 1 < x < 9}
E = {x | x = k², k ∈ ℕ and 1 < x < 9}
E = {2²}
E = {4}
• F = {x | x is an even number, 2 ≤ x < 9}
F = {2, 4, 6, 8}
So,
D ∩ F
= {..., – 3, – 2, – 1, 0, 1, 2, 3, ...} <span>∩ {2, 4, 6, 8}
</span>
= {2, 4, 6, 8} ≠ {4, 6}
Therefore, that statement is false.
I hope this helps. =)
Answer:
7a+1
Step-by-step explanation:
Okay so what you are supposed to do is simplify that for your answer. How you do this is by circling the things in common. So for example "4a" and "3a" are in common, so 4a plus 3a is 7a. Now look at the next things in common which would be "-5" and "6" add those together and you get 1.
27%
divide one hundred thirty five but the total of five hundred and move the decimal back two places